4. (a) Define the electromotive force and explain the physical mechanism of the electromotive force source. (b) One circuit has constructed by electromotive force source which has ɛ = 5V and inner resistivity r = values of R1 powers dissipated in R1, R2 and r. 1N. Two serial connected resistances which have 5N placed in that circuit. Calculate the IN and R2

College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter21: Circuits And Dc Instruments
Section: Chapter Questions
Problem 39CQ: An electronic apparatus may have large capacitors at high voltage in the power supply section,...
icon
Related questions
Question

it was an old question on exam, and I want know jow I can solve this question.

4. (a) Define the electromotive force and explain the physical mechanism of the
electromotive force source.
(b) One circuit has constructed by electromotive force source which has ɛ = 5V
and inner resistivity r = 12. Two serial connected resistances which have
values of R1
1N and R2
5N placed in that circuit. Calculate the
%3D
powers dissipated in R1, R2 and r.
• Gauss's law:
qin
€0
Here E is the electric field vector, da is the surface element vector, qin is the
total charge enclosed by the Gaussian surface, €o is the electric constant. The
integral is taken over the closed Gaussian surface.
• Electric potential at point P due to charge q is given by
V = k2.
1 q
4T€0 r
where r is the distance between the point P and the charge q. k = 9 x
10°NM2/C², eo
= 8.854 × 10-12C²/(Nm²).
• The power is defined by
P = VI = I²R= V² /R
Transcribed Image Text:4. (a) Define the electromotive force and explain the physical mechanism of the electromotive force source. (b) One circuit has constructed by electromotive force source which has ɛ = 5V and inner resistivity r = 12. Two serial connected resistances which have values of R1 1N and R2 5N placed in that circuit. Calculate the %3D powers dissipated in R1, R2 and r. • Gauss's law: qin €0 Here E is the electric field vector, da is the surface element vector, qin is the total charge enclosed by the Gaussian surface, €o is the electric constant. The integral is taken over the closed Gaussian surface. • Electric potential at point P due to charge q is given by V = k2. 1 q 4T€0 r where r is the distance between the point P and the charge q. k = 9 x 10°NM2/C², eo = 8.854 × 10-12C²/(Nm²). • The power is defined by P = VI = I²R= V² /R
Expert Solution
steps

Step by step

Solved in 5 steps

Blurred answer
Knowledge Booster
Relativistic speed and time
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781938168000
Author:
Paul Peter Urone, Roger Hinrichs
Publisher:
OpenStax College
University Physics Volume 2
University Physics Volume 2
Physics
ISBN:
9781938168161
Author:
OpenStax
Publisher:
OpenStax
College Physics
College Physics
Physics
ISBN:
9781285737027
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
Inquiry into Physics
Inquiry into Physics
Physics
ISBN:
9781337515863
Author:
Ostdiek
Publisher:
Cengage
Glencoe Physics: Principles and Problems, Student…
Glencoe Physics: Principles and Problems, Student…
Physics
ISBN:
9780078807213
Author:
Paul W. Zitzewitz
Publisher:
Glencoe/McGraw-Hill
An Introduction to Physical Science
An Introduction to Physical Science
Physics
ISBN:
9781305079137
Author:
James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:
Cengage Learning