4. Assume that you have 0.001 Fe* and 0.002 Fe2* (i.e., the solution contains Ferrous and Ferric chloride) in the solution and then use the Nernst equation to calculate the Nernst potential vs. SCE for each half cell reaction. Two parts: One half cell reaction is Fe3+ + e- = Fe²*. The second half cell reaction is Fe = Fe2+ + 2e-. Which one is the anode, which one the cathode?
4. Assume that you have 0.001 Fe* and 0.002 Fe2* (i.e., the solution contains Ferrous and Ferric chloride) in the solution and then use the Nernst equation to calculate the Nernst potential vs. SCE for each half cell reaction. Two parts: One half cell reaction is Fe3+ + e- = Fe²*. The second half cell reaction is Fe = Fe2+ + 2e-. Which one is the anode, which one the cathode?
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.48QE: The standard potential of the cell reaction Ag+(aq)+Eu2+(aq)Ag(s)+Eu3+(aq) is E = +1.23 V. Use the...
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