4. Buffer capacity is a measure of the extent to which a buffer can resist a change in pH upon the addition of a strong acid or strong base. When a strong acid is added to a buffer solution it will react with the weak base to produce wea acid without dramatically changing the mol ratio (mol A-/mol HA). Complete the ICE table below to show the change occurring and calculate the equilibrium for the addition of 0.10 mol of H* added to a buffer consisting of 1.0 mol HA and 1.0 mol A (with a pKa = 9.00 and initial buffer pH of 9.00) The initial values have %3D already been included in the table. A +H* HA mol A mol H* mol HA Initial 1.0 0.10 1.0 Change Equilibrium Using the equilibrium values from the table above and the Henderson-Hasselbalch equation on page 81, calculate the pH after the addition of acid. Neutial s acid to produce we
4. Buffer capacity is a measure of the extent to which a buffer can resist a change in pH upon the addition of a strong acid or strong base. When a strong acid is added to a buffer solution it will react with the weak base to produce wea acid without dramatically changing the mol ratio (mol A-/mol HA). Complete the ICE table below to show the change occurring and calculate the equilibrium for the addition of 0.10 mol of H* added to a buffer consisting of 1.0 mol HA and 1.0 mol A (with a pKa = 9.00 and initial buffer pH of 9.00) The initial values have %3D already been included in the table. A +H* HA mol A mol H* mol HA Initial 1.0 0.10 1.0 Change Equilibrium Using the equilibrium values from the table above and the Henderson-Hasselbalch equation on page 81, calculate the pH after the addition of acid. Neutial s acid to produce we
Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 2RQ: Define a buffer solution. What makes up a buffer solution? How do buffers absorb added H+ or OH with...
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Complete the ICE table below to show the change occurring and calculate the equilibrium for the addition of 0.10 mol of H+ added to a buffer consisting of 1.0 mol HA and 1.0 mol A- (with a pKa=9.00)
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