4. Divide moles of NaCl by moles of starting material a. NaHCO3 X Mol NaCl = X mol ratio X mol NaHCO, b. Na,CO3 X Mol NaCl = X mol ratio X mol Na,CO3

Chemistry by OpenStax (2015-05-04)
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Chapter4: Stoichiometry Of Chemical Reactions
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Problem 75E: How many molecules of the sweetener saccharin can be prepared from 30 C atoms, 25 H atoms, 12 0...
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4. Divide moles of NaCl by moles of starting material
a. NaHCO3
X Mol NaCl
= X mol ratio
X mol NaHCO,
b. Na,CO3
X Mol NaCl
= X mol ratio
X mol Na,CO3
Transcribed Image Text:4. Divide moles of NaCl by moles of starting material a. NaHCO3 X Mol NaCl = X mol ratio X mol NaHCO, b. Na,CO3 X Mol NaCl = X mol ratio X mol Na,CO3
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