4. Following are the results of a field unit weight determination test on a soil with sand cone method: • Calibrated dry density of Ottawa sand = 1667 kg/m • Calibrated mas of Ottawa sand to fill the cone = 0.117 kg • Mass of jar + cone + sand (before use) = 5.78 kg • Mass of jar + cone + sand (after use) = 2.85 kg • Mass of moist soil from hole = 3.42 kg Moisture content of moist soil =13.6% Find the dry unit weight of the soil

4. Following are the results of a field unit weight determination test on a soil with sand cone method: • Calibrated dry density of Ottawa sand = 1667 kg/m • Calibrated mas of Ottawa sand to fill the cone = 0.117 kg • Mass of jar + cone + sand (before use) = 5.78 kg • Mass of jar + cone + sand (after use) = 2.85 kg • Mass of moist soil from hole = 3.42 kg Moisture content of moist soil =13.6% Find the dry unit weight of the soil

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter5: Soil Compaction

Section: Chapter Questions

Problem 5.7P

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The following are the results of a field unit weight determination test performed on the soil by means of the sand cone method. Calibrated dry density of Ottawa sand = 1570 kg/m3 Calibrated mass of Ottawa sand to fill the cone = 0.545 kg Mass of jar + cone + sand (before use) = 7.59 kg Mass of jar + cone + sand (after use) = 4.78 kg Mass of moist soil dug from hole = 3.007 kg Water content of moist soil = 10.2% Max dry unit weight = 19 kN/m3 Find the dry unit weight in kN/m3.
with figures if necessary 1. A wet sand sample has a volume of 4.64 x 10-4 m3 and weighs 8 N. After oven-drying, the weight reduces to 7.5 N. Calculate the water content, void ratio, and degree of saturation. 2. The mass of a wet sample of soil and its container is 0.33 kg. The dry mass of the soil and its container is 0.29 kg. The mass of the container is 0.06 kg and its volume is 0.15 x 10-3 m3. Determine the bulk, dry and saturated unit weights of the soil. Determine the void ratio and degree of saturation. Determine the amount of air void in the soil and the water of water required to saturate 1 m3 of the soil. 3. A sand has a natural water content of 5% and bulk unit weight of 18.0 kN/m3. The void ratios corresponding to the densest and loosest state of this soil are 0.51 and 0.87. Find the relative density and degree of saturation.
A soil specimen has a volume of 0.05 m3 and a mass of 87.5 kg. Given: w = 15%, Gs = 2.68. Determine Porosity.
Following are the results of a field unit weight determination test performed by means of the sand cone method:• Calibrated dry unit weight of Ottawa sand = 104 lb/ft3• Weight of Ottawa sand to fill the cone = 0.258 lb• Weight of jar + cone + sand (before use) = 13.4 lb• Weight of jar + cone + sand (after use) = 6.39 lb• Weight of moist soil from hole = 7.3 lb• Moisture content of moist soil = 11.6%Determine: Dry unit weight of compaction in the field.
A saturated soil sample (S=100%) contains 28 g of soil solids and 22 g of water. The void ratio is 2.2. Calculate the following Water content (w), = porosity (n) = total (wet) density (ρT) = ____ g/cm3 dry density (ρd ) = ______ g/cm3 total unit weight (γT ) = ______ kN/m3 and specific gravity (Gs) of the soil solids = Adjust your answer to TWO decimal places. Provide step by step solution.
(a) Mass of jar with cone and sand (before use) = 4950 g, (b) mass of jar with cone and sand (after use) = 2280 g, (c) mass of soil from the hole = 2925 g, (d) dry density of sand = 1.48 g/cm3, (e) water content of the wet soil = 12%. Determine the dry unit weight of compacted soil.
A fully saturated soil sample has a volume of 28 cc. The sample was dried in oven and the weight of the dry soil pat was found to be 48.76 g. Given G= 2.68. Determine void ratio in percent. a. 18.23 b. 53.6 c. 9.77 d. 20.0
Following are the results of a field unit-weight determination test performed on the same soil by means of the sand cone method: -Calibrated dry unit weight of Ottawa sand = 15.4019 kn/m3 -Calibrated weight of Ottawa sand to fill the cone = 5.3496 N -Weightof jar + cone + sand (before use) = 74.451 N -Weightof jar + cone + sand (after use) = 46.886 N -Weight of moist soil from hole = 29.509 N -Moisture content of moist soil = 10.21% DETERMINE AND SHOW COMPLETE SOLUTION 1. Dry density of compaction in the field in kg/cu.m.
A Cylindrical soil sample of 7.5 cm height and 3.75 cm diameter has been prepared at the shrinkage limit. If the sample is now allowed to absorb water so that its water content reaches the liquid limit, what will be its volume? Given ?? = 62%, ?? = 34%, ?? = 21%, and ?s = 2.68.
A fully saturated clay sample has a mass of 1526 grams. After oven-drying, its mass was reduced to 1053 grams. The specific gravity of soil particles is 2.7. Calculate the porosity in percent (%). Select one: a. 25.17 b. 43.19 c. 54.81 d. 32.52
A proctor compaction test was conducted on a soil sample, and the following observations weremade:Water content, percent 7.7 11.5 14.6 17.5 19.7 21.2Mass of wet soil, g 1739 1919 2081 2033 1986 1948 1. determine the wet density in g/cm32. determine the dry density in g/cm33. determine the dry unit weight in kN/m34. construct the compaction curve 5. determine the optimum moisture content in percent 6. determine the maximum dry density in kN/m37. construct the 80% and 100% saturation lines using w% = 8, 12, 16, 20, and 24 8. calculate the saturation for the maximum dry density (ϒdmax in kN/m3) and the optimummoisture content (wopt %)
in a partially saturated soil e (void ratio) = 1.2; w = 30%; Ss = 2.66; calculate the γm(specific gravity of soil mass) and γd (dry specific weight of sample) of said soil. complete the diagram show in the image. I WILL RATE IT.