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- Hematite is an iron ore with the following composition: Fe2O3 [MW=159.70]. To make steel, carbon [At. Wt. = 12.01] in the form of coke is used to reduce Fe2O3 to iron metal [At. Wt. = 55.85] as shown below: 3 C + 2 Fe2O3 → 3 CO2 + 4 Fe How many grams of carbon are needed to produce 2,500 grams of iron? Relative to the problem the processing of 798.5 g of hematite ore produced 508.2 g of iron metal. Determine the percent yield of pure iron for this batch?What is the concentration of ions in the soil solution after fertilizer application? Suppose that 122 pounds of K+ were applied per acre, then a gentle rain soaked the top 10 inches of soil to field capacity, which for the given soil was about 16% water by volume. If the K+ was applied as KCl, it is plausible that it all dissolved and distributed relatively uniformly with the infiltrating water. If so, then what was the K+ concentration in the soil solution in mol K+/L solution? Note that the volume can be computed like we do for an acre-furrow-slice (AFS), as area times depth. This is going to be a relatively small number, so please report your answer in mol K+/L solution to at least 5 decimal places.Electrolytic manganese dioxide can be prepared from manganese carbonate ore by crushing,milling and leaching the ore in sulphuric acid. Manganese sulphate is crystallised from thesolution, redissolved and electrolysed to give the manganese dioxide.If the crystallisation were performed in a 30m3 tank and the concentration of the solutionentering the tank were 160 grams per litre and left the tank at 40 grams per litre, how muchMnSO4.5H2O would be produced.
- The mercury in a 0.8142-g sample was precipitated with an excess of paraperiodic acid, H5IO6: 5 Hg 2+ + 2 H5IO6 ---> Hg5(IO6)2 (s) + 10 H + The precipitate (MW = 1448.8 g/mol) was filtered, washed free of precipitating agent, dried, and weighed, and 0.4114 g was recovered. Calculate the a) % Hg (200.6 g/mol) b) % Hg2Cl2 (472.1 g/mol)An impure sample of Na3PO3 weighing 0.1392 g was dissolved in 25 mL of water. A solution containing 50 mL of 3% w/v mercury(II) chloride, 20 mL of 10% w/v sodium acetate, and 5 mL of glacial acetic acid was then prepared. The solution containing the phosphite was added dropwise to the second solution, oxidizing PO3^3– to PO4^3– and precipitating Hg2Cl2. After digesting, filtering, and rinsing, the precipitated Hg2Cl2 was found to weigh 0.4320 g. Report the purity of the original sample as %w/w Na3PO3. Moles Na3PO3 = moles Hg2Cl2Fe2O3 is produced from a pyrite concentrate containing 65% by weight of pyrite (FeS2) by total oxidizing roasting according to the following reaction. 5 tons of pyrite concentrate is roasted daily (MA, g / mol; Fe: 56; S: 32; 0: 16; H: 1). 2FeS2 + 11 / 2O2 → Fe2O3 + 4SO2 How much Fe2O3 is produced in 1 day?
- 0.1724g of a mineral containing MnO₂ was dissolved and then treated with excess iodide according to the following unbalanced reaction: MnO2(s) + H+ → Mn²+ + I2 + H₂O The I₂ released was titrated with a solution of Na₂S2O3 0.07320 mol/L, requiring 14.65 mL to reach the point end of degree a) Determine the percentage of MnO₂ in the ore. b) When iodine solutions are used as titrants these are prepared by dissolving 1₂ in concentrated KI. Explain the reason for the need for KI in the preparation of these solutions?Balance, what is he coefficient in front H2SO4?Formula mass: K2CO3, 138.21; KHCO3, 100.12; K, 39.10; C, 12.01; O, 16.00; and H, 1.01 A 2.126 g sample of a solid mixture containing only K2CO3 and KHCO3 is dissolved in water. A volume of 32.50 mL of 0.753 M HCl standard solution is required to titrate the mixture to a bromocresol green end point. Calculate the weight percent of potassium in the mixure.
- An impure sample of Na3PO3 weighing 0.1 g is dissolved in 35 mL of water. A solution containing 45 mL of 3% w/v HgCl2, 30 mL of 10% w/v sodium acetate, and 10 mL of glacial acetic acid is then prepared. After digesting, filtering, and rinsing the precipitate, 0.2857 g of Hg2Cl2 is obtained. Report the purity of the original sample as % w/w Na3PO3.A stock solution of potassium permanganate (KMn04) was prepared by dissolving 13.0g KMn04 with DI in a 100ml volumetric flask and diluting to the calibration mark. Determine the molarity of the solution.You have a 500mM stock solution of NaCl (formula weight: 58.4g/mole), a 0.25M stock solution of glucose (Formula Weight: 180.2g/mole), a bottle of alanine, solid form (Formula Weight: 89.09g/mole), and a bottle of Tris base, solid form (formula weight: 121.1g/mole). How would you prepare 250mL of a single solution containing 25mM Tris, 15mM glucose, 0.15M NaCl, and 2.5% (w/v) alanine?