You have a 500mM stock solution of NaCl (formula weight: 58.4g/mole), a 0.25M stock solution of glucose (Formula Weight: 180.2g/mole), a bottle of alanine, solid form (Formula Weight: 89.09g/mole), and a bottle of Tris base, solid form (formula weight: 121.1g/mole). How would you prepare 250mL of a single solution containing 25mM Tris, 15mM glucose, 0.15M NaCl, and 2.5% (w/v) alanine?

You have a 500mM stock solution of NaCl (formula weight: 58.4g/mole), a 0.25M stock solution of glucose (Formula Weight: 180.2g/mole), a bottle of alanine, solid form (Formula Weight: 89.09g/mole), and a bottle of Tris base, solid form (formula weight: 121.1g/mole). How would you prepare 250mL of a single solution containing 25mM Tris, 15mM glucose, 0.15M NaCl, and 2.5% (w/v) alanine?

Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter7: Solutions And Colloids

Section: Chapter Questions

Problem 7.107E

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