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You have a 500mM stock solution of NaCl (formula weight: 58.4g/mole), a 0.25M stock solution of glucose (Formula Weight: 180.2g/mole), a bottle of alanine, solid form (Formula Weight: 89.09g/mole), and a bottle of Tris base, solid form (formula weight: 121.1g/mole). How would you prepare 250mL of a single solution containing 25mM Tris, 15mM glucose, 0.15M NaCl, and 2.5% (w/v) alanine?

Question

You have a 500mM stock solution of NaCl (formula weight: 58.4g/mole), a 0.25M stock solution of glucose (Formula Weight: 180.2g/mole), a bottle of alanine, solid form (Formula Weight: 89.09g/mole), and a bottle of Tris base, solid form (formula weight: 121.1g/mole). How would you prepare 250mL of a single solution containing 25mM Tris, 15mM glucose, 0.15M NaCl, and 2.5% (w/v) alanine?

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Step 1

The volume of 500mM NaCl required to prepare 0.15M NaCl is calculated as,

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Step 2

The volume of 0.25M glucose required to prepare 15mM glucose is calculated as,

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Step 3

The amount of tris required to prepar...

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