Im confuse on how to solve this exercise Н-Н436 kJ/molС-Н413 kJ/molC=C614 kJ/molH-CIC-CC-NC-O431 kJ/mol348 kJ/mol839 kJ/molH-F567 kJ/mol293 kJ/mol799 kJ/molN-H391 kJ/mol358 kJ/mol495 kJ/molN-OO-H201 kJ/molС-F485 kJ/mol1072 kJ/mol463 kJ/molC-CI328 kJ/mol615 kJ/mol418 kJ/mol941 kJ/mol891 kJ/molO-0146 kJ/molC-S259 kJ/molN=NF-F155 kJ/molCI-CI242 kJ/molN=NC=NEstimate the enthalpy change (A Hrxn) of the following reaction for 5 moles of Cl2 using the bond energiesabove.H-H + CI-CI →→ H-CI + H-CIkJ

Answered: Image /qna-images/answer/058abc0b-32a6-4d3b-b95d-362db1ea9cd4.jpg

436 kJ/mol 431 kJ/mol 567 kJ/mol 413 kJ/mol 348 kJ/mol 293 kJ/mol C=C 614 kJ/mol H-H H-CI C-H C-C C=C 839 kJ/mol 799 kJ/mol H-F C-N C-O C-F N-H 391 kJ/mol 358 kJ/mol 495 kJ/mol N-O 201 kJ/mol 485 kJ/mol C=O 1072 kJ/mol O-H O-0 C=N N=N 463 kJ/mol 328 kJ/mol 615 kJ/mol C-S CI-CI 146 kJ/mol 259 kJ/mol 418 kJ/mol F-F 155 kJ/mol 242 kJ/mol N=N 941 kJ/mol C=N 891 kJ/mol Estimate the enthalpy change (A Hrxn) of the following reaction for 5 moles of Cl2 using the bond energies above. H-H + CI-CI → H-CI + H-CI kJ

436 kJ/mol 431 kJ/mol 567 kJ/mol 413 kJ/mol 348 kJ/mol 293 kJ/mol C=C 614 kJ/mol H-H H-CI C-H C-C C=C 839 kJ/mol 799 kJ/mol H-F C-N C-O C-F N-H 391 kJ/mol 358 kJ/mol 495 kJ/mol N-O 201 kJ/mol 485 kJ/mol C=O 1072 kJ/mol O-H O-0 C=N N=N 463 kJ/mol 328 kJ/mol 615 kJ/mol C-S CI-CI 146 kJ/mol 259 kJ/mol 418 kJ/mol F-F 155 kJ/mol 242 kJ/mol N=N 941 kJ/mol C=N 891 kJ/mol Estimate the enthalpy change (A Hrxn) of the following reaction for 5 moles of Cl2 using the bond energies above. H-H + CI-CI → H-CI + H-CI kJ

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter13: Structure Determination: Nuclear Magnetic Resonance Spectroscopy

Section13.SE: Something Extra

Problem 33AP

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