Calculate ΔH for 2 NO1g2 + O21g2 ¡N2O41g2, using thefollowing information:N2O41g2¡2 NO21g2 ΔH = +57.9 kJ2 NO1g2 + O21g2 ¡2 NO21g2 ΔH = -113.1 kJ(a) 2.7 kJ (b) -55.2 kJ (c) -85.5 kJ (d) -171.0 kJ (e) +55.2 kJ

Chemistry for Engineering Students
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Chapter10: Entropy And The Second Law Of Thermodynamics
Section: Chapter Questions
Problem 10.46PAE: 10.46 Discuss the effect of temperature change on the spontaneity of the following reactions at 1...
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Calculate ΔH for 2 NO1g2 + O21g2 ¡N2O41g2, using the
following information:
N2O41g2¡2 NO21g2 ΔH = +57.9 kJ
2 NO1g2 + O21g2 ¡2 NO21g2 ΔH = -113.1 kJ
(a) 2.7 kJ (b) -55.2 kJ (c) -85.5 kJ (d) -171.0 kJ (e) +55.2 kJ

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