5) Draw the possible structure for: C10H13CI NMR= 7.2 doublet of doublets (4H) 2.6 Hextet (1H) 1.6 quintet (2H) 1.6 doublet (3H) 1.1 triplet (3H)

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter5: Stereochemistry At Tetrahedral Centers
Section5.SE: Something Extra
Problem 26VC: Which of the following structures are identical? (Green = Cl.)
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5) Draw the possible structure for:
C10H13CI
NMR= 7.2 doublet of doublets (4H)
2.6 Hextet (1H)
1.6 quintet (2H)
1.6 doublet (3H)
1.1 triplet (3H)
Transcribed Image Text:5) Draw the possible structure for: C10H13CI NMR= 7.2 doublet of doublets (4H) 2.6 Hextet (1H) 1.6 quintet (2H) 1.6 doublet (3H) 1.1 triplet (3H)
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