5. (a) (b) (c) Studying the Temperature Dependence of the Rate Constant (k). The following reaction is studied at 3 different temperatures. Below you I will find the rate constant for a reaction determined at these temperatures. Use this data to answer the following questions k (min) 0.0409 min 0.0818 min -1 0.157 min -1 T (Celsius) 25.0 °C 35.0 °C 45.0 °C Calculate In k and 1/T and provide the values in the table below. In k 1/T (K¹) Plot In k vs. 1/T and attach the graph. It should be linear. A > B Calculate the slope of the graph of In k vs. 1/T. Show your work below. (d) Determine the Activation Energy of this reaction using the slope above. Show work below.

Chemistry for Engineering Students
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Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.57PAE
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5.
(a)
(b)
(c)
Studying the Temperature Dependence of the Rate Constant (k).
The following reaction is studied at 3 different temperatures.
Below you will find the rate constant for a reaction determined at
these temperatures. Use this data to answer the following questions
k (min
0.0409 min
0.0818 min
0.157 min -1
T (Celsius)
25.0 C
35.0 °C
45.0 C
Calculate In k and 1/T and provide the values in the table below.
In k
1/T (K-¹)
Plot In k vs. 1/T and attach the graph. It should be linear.
A B
Calculate the slope of the graph of In k vs. 1/T. Show your work below.
(d) Determine the Activation Energy of this reaction using the slope above. Show work below.
Transcribed Image Text:5. (a) (b) (c) Studying the Temperature Dependence of the Rate Constant (k). The following reaction is studied at 3 different temperatures. Below you will find the rate constant for a reaction determined at these temperatures. Use this data to answer the following questions k (min 0.0409 min 0.0818 min 0.157 min -1 T (Celsius) 25.0 C 35.0 °C 45.0 C Calculate In k and 1/T and provide the values in the table below. In k 1/T (K-¹) Plot In k vs. 1/T and attach the graph. It should be linear. A B Calculate the slope of the graph of In k vs. 1/T. Show your work below. (d) Determine the Activation Energy of this reaction using the slope above. Show work below.
Expert Solution
Step 1

The Arrhenius equation is lnk=-EaR1T+ constant

Ea = activaltion energyR is the gas constantT is the temperature in Kelvink is the rate constant

The Arrhenius equation is in the straight line form y=mx+b with slope=-EaR 

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