5. In a random sample of 400 college students, 16 had perfect attendance Find the 95% confidence interval for the proportion of students with perfect attendance. Interpret the confidence interval.

Q: If n=380 and p^(p-hat) =0.12, find the margin of error at a 95% confidence level Give your answer…

A: Given data: n = 380  p^(p-hat) =0.12, To find : The margin of error at a 95% confidence level

Q: 12. In a sample of 600 Canadians, 265 say they would rather retire in the US than in Canada.…

A:

Q: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If…

A: Given information Error = 4% = 0.04 Confidence level = 0.95

Q: 2. A nutritionist wants to know the population proportion of Grade 1 learners who eat vegetables.…

A: We have given thatn = 1200x = 200p̂ = x/n = 200/1200 = 0.167Significance level (α) = 1 - 0.95 = 0.05

Q: In a study of 200 accidents that required treatment in an emergency room, 80 occurred at work. Find…

A: Obtain the 90% confidence interval for the true proportion of accidents that occurred at work. The…

Q: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If…

A: Given information Error = 2% = 0.02 Confidence level = 0.95

Q: In a survey of 3234 adults aged 57 through 85​ years, it was found that 88.9% of them used at least…

A:

Q: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If…

A:

Q: In one city, 59.6% of the 1500 students surveyed said they eat at the school cafeteria. Find the 95%…

A: Given, Sample size=n=1500 p^=0.596 α=0.05

Q: 1. Suppose survey results say that 69% of the adult females from a sample taken in the United States…

A: Proportion (p) = 69 %  Margin of Error (E) = 3%  Alpha = 95%  FIRSTLY calculate the confidence…

Q: 1. A poll of 2,500 people shows that 50% approve of a smoking ban in bars and restaurants. What is…

A:

Q: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If…

A: According to the provided information, The z score at 95% confidence interval from the standard…

Q: In the Framingham Offspring study 3630 subjects were on anti-hypertensive medication out of 4657…

A: Note: Hi, thank you for the question. As per our company guideline we are supposed to answer only…

Q: In a survey of 3473 adults aged 57 through 85​ years, it was found that 84.6% of them used at least…

A:

Q: If n=380 and p (p-hat) =0.52, find the margin of error at a 95% confidence level Give your answer to…

A: Dear student, If you find this solution helpful please upvote ? it. The solution is given below:

Q: 5-Seventy percent of 50 randomly selected students from college of science and engineering were…

A:

Q: 4. The Department of the Treasury is interested in finding out what proportion of people support…

A: Given that  Population proportion p=15%=0.15 Margin of error =E =2%=0.02 95% confidence.  NOTE:-…

Q: In a survey of 3485 adults aged 57 through 85​ years, it was found that 86.4​% of them used at least…

A:

Q: A random sample of 600 voters in Centreville indicated that 90 of them believed their congressional…

A: Formula for confidence interval for population proportion : CI =p^ ± E  Where ,  p^ is sample…

Q: If n=270 and p (p-hat) =0.93, find the margin of error at a 90% confidence level Give your answer to…

A:

Q: 9. A survey found that out of 900 workers, 150 said they were interrupted by frank phone calls. Find…

A:

Q: If n=340 and p (p-hat) =0.23, find the margin of error at a 95% confidence level Give your answer to…

A: Given,n=340p^=0.23α=1-0.95=0.05α2=0.025Z0.025=1.96

Q: If n=530 and ˆpp^ (p-hat) =0.51, find the margin of error at a 90% confidence level Give your…

A:

Q: If n=270 and ˆpp^ (p-hat) =0.59, find the margin of error at a 99% confidence level Give your…

A: Given  n=270, pcap=0.59, alpha=0.01 Zcritical=2.578 at alpha=0.01 We want to find margin of error

Q: If n=110 and ˆpp^ (p-hat) =0.71, find the margin of error at a 90% confidence level Give your…

A: Sample size n = 110 Sample proportion p^ = 0.71 Confidence level = 90% Formula Used: Margin of error…

Q: If 64% of a sample of 550 people leaving a shopping mall claims to have spent over $25 create and…

A: Given,   Sample size = 550 Sample proportion = 0.64   Critical value: Using z-table, the z-critical…

Q: If n=510 and p (p-hat) =0.47, find the margin of error at a 90% confidence level Give your answer as…

A:

Q: If n= 220, p-hat= .4, then what will be the 87.4% confidence interval for the population proportion?

A:

Q: Suppose we know that a confidence interval for a population proportion is (0.572, 0.662), with a…

A:

Q: 4. How large a sample must be taken to estimate the proportion of households in which a cell phone…

A: In probability theory, a normal distribution is a type of continuous probability distribution for a…

Q: If n=530 and ˆpp^ (p-hat) =0.75, find the margin of error at a 90% confidence level Give your…

A: Givenn=530p^=0.75confidence level=90%

Q: If n=580 and ˆpp^ (p-hat) =0.59, find the margin of error at a 95% confidence level Give your…

A: Obtain the margin of error for the 95% confidence interval. The margin of error for the 95%…

Q: If n=490 and ˆpp^ (p-hat) =0.54, find the margin of error at a 90% confidence level Give your…

A:

Q: 3. Aresearcher wants to estimate the daily expenses of college students. He wants a 99% confidence…

A:

Q: If n=350 and ˆpp^ (p-hat) =0.64, find the margin of error at a 90% confidence level Give your…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: Suppose you are designing a survey of firework plans among Kansas residents. You would like for the…

A: Here we need to find the required sample size with a 95% confidence level to estimate the number of…

Q: Suppose you want to construct an 80% confidence interval for the proportion of businesses that…

A: Given:Margin of Error (E)=3.5%=0.035   For Confidence level 80%, the significance level (α) is…

Q: If n=200 and ˆpp^ (p-hat) =0.16, find the margin of error at a 95% confidence level Give your…

A: Given Information

Q: A recent study of 750 internet users in Europe found that 35% of internet users were women. What is…

A: It is given that the study of 750 internet users in Europe found that 35% of internet users were…

Q: If n=380 and p (p-hat) =0.49, find the margin of error at a 99% confidence level Give your answer to…

A: Answer - If n = 380,   P^ = 0.49                  99% confidence interval         ⇒ α =1 - 0.99 =…

Q: (d) Use the combined data of 80 students, construct a 95% confidence interval estimate of the…

A: Given that  Total students=n=40+40=80 Number of pass students=X=28+32=60

Q: At one large college, 660 out of the 1500 students surveyed said they plan to take another science…

A: Given that,   x=660,n=1500 The sample proportion is, Critical values: By using the standard normal…

Q: Suppose we know that a confidence interval for a population proportion is (0.105,0.355), with a…

A: Obtain the margin of error. The margin of error is obtained below: Margin of Error: The margin of…

Q: If n=480 and p^ (p-hat) =0.45, find the margin of error at a 90% confidence level Give your answer…

A:

Q: Suppose you calculate a 99% confidence interval of 14.71 to 21.64. Determine the margin of error.

A: Given information- We have given a value of 99% confidence interval is- C.I = (14.71, 21.64) Lower…

Q: Aston’s Career Service wants to find out what proportion of Aston’s students work in a part-time…

A: From the given information, Population proportion = p = 60% = 0.60 Margin of error = E = 4% = 0.04…

Q: If n=410 and p (p-hat) =0.47, find the margin of error at a 90% confidence level Give your answer to…

A: The random variable X follows binomial distribution. The sample size is 410. The sample proportion…

Q: Suppose that based on a random sample, a 95% confidence interval for the mean hours slept (per day)…

A:

Q: If n=360 and ˆp(p-hat) =0.69, find the margin of error at a 95% confidence level

A: