Direction: Read and understand the ff. set of monohybrid cross problems andanswer each problem by showing the Punnett square, genotypes andphenotypes.5. In humans, being a tongue roller (R)who is a non-roller marries a woman who is heterozygous for tongue rolling.dominant over non-roller (r). A mana. Father's phenotype:b. Father's genotype:c. Mother's phenotype:d. Mother's genotype:

The relationship between two gene variants is referred to as dominant. Each parent gives each child…

Answered: 5. In humans, being a tongue roller (R)…

5. In humans, being a tongue roller (R) is di who is a non-roller marries a woman who a. Father's phenotype: p. Father's genotype: C. Mother's phenotype: d. Mother's genotype:

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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I. Perform the indicated single-gene and two-gene crosses. Show all work. Show all Punnett squares. List the gene or genes involved, list and define all allele symbols, and indicate the genotypes of the individuals you are crossing above the Punnett square. Answer questions that ask for a ratio as a ratio and questions that ask for a percent as a percent. One form of red-green color blindness is an X-linked recessive trait. A heterozygote woman has children with a normal man. What is the percentage chance that they will have a child with color blindness?
I. Perform the indicated single-gene and two-gene crosses. Show all work. Show all Punnett squares. List the gene or genes involved, list and define all allele symbols, and indicate the genotypes of the individuals you are crossing above the Punnett square. Answer questions that ask for a ratio as a ratio and questions that ask for a percent as a percent. In humans, albinism is a recessively determined trait. One form of hereditary deafness is also a recessive trait. Show the cross of a man who is heterozygous for skin pigmentation and heterozygous for hereditary deafness with a woman who is albino and deaf. Show the expected phenotype ratio of the offspring.
Monohybrid Cross Worksheet Directions: Answer each of the following questions using a Punnett Square and the rules of monohybrid crosses. The allele for dimples (D) is dominant to the allele for no dimples (d). A man heterozygous for dimples marries a woman who is also heterozygous for dimples. What is the man’s genotype and the woman’s genotype? What is the man’s phenotype and the woman’s phenotype? Do a cross to determine all potential dimple genotypes and phenotypes for the offspring of this man and woman. The allele for hitchhiker’s thumb (h) is recessive to straight thumb (H). If a man and his wife are both homozygous recessive, will any of their offspring potentially have hitchhikers thumb? What is the man’s genotype and the woman’s genotype? What is the man’s phenotype and the woman’s phenotype? What genotype(s) must the offspring have in order to have the phenotypic trait of hitchhiker’s thumb? Do a cross to determine all potential hitchhiker’s…
Complete the sentences You cross two mice with wildtype (long) tails and collect a male offspring with a short tail, who you name Squeak. Tail length is controlled by the gene Lf, which is a paternally imprinted gene in mice. Given that this is an imprinted gene, explain the inheritance and expression of the trait. 1. Squeak’s short tail allele was inherited from the _____ (female, male, or either) parent. That parent did not express the trait because the allele was ____ (unmethylated, methylated) in the parent’s somatic cells and was inherited from that parent’s own ___ (mother, father, either mother or father)2. If Squeak’s offspring inherit the short tail allele from Squeak, will they have short tails? Yes or No?3. If Squeak was a female instead of a male, which answers in this question would change? ____ (some of the answers, all of the answers, or only the one about the offspring)
A. HUMAN PEDIGREE CASE ANALYSIS1. One couple has three children with the following sexes and ages: one son (40 y.o.) and two daughters (35 y.o. and 33 y.o.), all of them have normal pigmentation. Another couple has a son (35 y.o) and a daughter (20 y.o.) and all of them also have normal pigmentation. Both couples have normal pigmentation. The younger daughter from the first couple married the son of the second couple and they had three children. Their eldest daughter (5 y.o.) has normal pigmentation while their only son (3 y.o.) and one daughter (1 y.o.) have albinism. a. Draw the pedigree of this family. Follow protocols in making a pedigree. Provide the genotype of all individuals in the pedigree. Please provide also the gene notation. b. What is the mode of inheritance of this trait? c. Justify your answer in letter (b).d. For their normal daughter, what is the probability that she is a carrier? Show solution. e. If they will have a fourth child, what is the probability that the…
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Please help answer question 1 What would a pedigree of Greg and Olga’s families look like? Concentrate simply on family relationships and aff ected persons.
d. Write the genotypes of the parents used in the testcross using the correct notation Please I really need help with this thanks
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identify if it is True or False 1. ABO Blood Group show codominance. 2. Alleles are different forms of genes. 3. Sex-linked inheritance means that only the X-chromosomes are affected. 4. The carriers of hereditary materials are the genes. 5. Hemophilia is a sex-linked trait.
7. Mr. and Mrs. Weasley have 7 children and all of the children have red hair like their parents. Mrs. Weasley has brown eyes but Mr. Weasley's eye color is unknown. Four of their 7 children have blue eyes and three have brown eyes. a. I Mr. Weasley's eye color is blue, what must be Mrs. Weasley's genotype? Explain how you arrive at your answer. Draw a Punnett square to support your answer. Explanation
1. Hemophilia is due to a sex-linked gene. It is recessive and found on the X chromosome. A woman who is a carrier for hemophilia marries a normal man. What will be the possible phenotypes of their children? Use a punnet square. 2. A phenotypically normal man, who has a hemophiliac brother, marries a normal woman, who is not a carrier. What is the probability that any of their children will be hemophiliac? Use a punnet square. 3. Color-blindness is an X-linked, recessive trait. If a normal-sighted woman, whose father was color-blind, marries a colorblind man, what is the probability that they will have a son who is color-blind? Use a punnet square. 4. A man and woman, both of normal vision, have: 1) a color-blind son (#1) who has a daughter of normal vision 2) a daughter (#1) of normal vision who has one color-blind son and one normal vision son 3) another daughter (#2) of normal vision who has five sons, all with normal vision What are the probable genotypes of the…