Answer 1 only (If you could use short ways to solve, it is highly appreciated) XERCISE IV- 3.50.00mL of a solution containing both Ni2* and Pb2+ ions requires 46.32 mL of a 0.02041M EDTAsolution for titration of both metals. A second 50.00 mL aliquot is treated with KCN to maskthe nickel and then titrated with 30.28 mL of the same EDTA solution. Calculate the molaritiesof the Ni2 and Pb2+ ions.2. A 0.5745 g sample of an alloy containing principally bismuth and lead is dissolved in nitric acid anddiluted to 250.0 mL in a volumetric flask. A 50.00 mL aliquot is withdrawn, the pH adjusted to 1.5,and the bismuth titrated with 30.26 mL of 0.01024 M EDTA. The pH of the solution is thenincreased to 5.0 and the lead titrated with 20.42 mL of the same EDTA solution. Calculate thepercentages of lead and bismuth in the alloy.3. A standard solution of EDTA is prepared, and by titration each mL is found to complex with theMg in 10.0 mL of a solution containing 0.300 g of MgCl2 per liter. A 100 mL pipetful of a certainwell water is found to require 8.60 mL of the standard EDTA. With the knowledge that theconventional method of expressing water hardness in terms of ppm of CaCO3 regardless of thenature of the cations and anions actually present, what is the hardness of the well water?4. A 60.00 mL of buffered solution (pH 10) containing Zn and Nit ions (from a chip sample) isanalyzed using EDTA titration with EBT as indicator. The following data were recorded:M of EDTA = 0.05204 M=D41.97 mL= 15.16 mLHow many mmoles of Zn and Ni were present in the solution ? If the weight of the chip isV of EDTA for ZN2+V of EDTA for Ni2+1.000 g, give the % Zn and % Ni in the original sample.-54-

1) Given: Volume of solution = 50.00 mL. Concentration of EDTA = 0.02041 M Volume of EDTA required…

50.00 mL of a solution containing both Ni* and Pb2* ions requires 46.32 mL of a 0.02041 M EDTA solution for titration of both metals. A second 50.00 mL aliquot is treated with KCN to mask the nickel and then titrated with 30.28 mL of the same EDTA solution. Calculate the molarities of the Ni2 and Pb2* ions. acid and

50.00 mL of a solution containing both Ni* and Pb2* ions requires 46.32 mL of a 0.02041 M EDTA solution for titration of both metals. A second 50.00 mL aliquot is treated with KCN to mask the nickel and then titrated with 30.28 mL of the same EDTA solution. Calculate the molarities of the Ni2 and Pb2* ions. acid and

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter17: Complexation And Precipitation Reactions And Titrations

Section: Chapter Questions

Problem 17.34QAP

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