Q: a. A deepwell water sample of 100 mL was titrated with 0.010 M EDTA at pH 10 ( with Mg-EDTA pH 10…
A: According to Q&A guidelines of Bartleby, we are supposed to answer only the first question out…
Q: Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to…
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Q: A 17.50 mL solution containing Zn2+ was treated wth 40.00 mL of 0.0600 M EDTA to complex all of the…
A: The volume of zinc solution is 17.50 mL. The volume of 0.0600 M EDTA that is made to react with zinc…
Q: What is the pM in a titration of 20.0 mL of 0.05 M Ca2 with 0.05 M EDTA if the titration is buffered…
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Q: Chromium (III) ion was complexed with EDTA and determined via back-titration. Given the following…
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Q: Calculate the pSr value for 10 mL of EDTA in the titration of 50 mL of 0.02 M Sr2 + in an…
A: Concentration of Sr2+ 0.02 M. Volume of Sr2+ is 50 mL=0.050 L Moles of Sr2+: nSr2+=MSr2+VSr2+…
Q: In order to adjust the EDTA solution, 10 mL of 0.01M Ca + 2 sample was taken and 10 mL of pH 10…
A: Ca2+ ions forms a complex compound with EDTA ligand. One mole of Ca2+ inos form complex with one…
Q: Calculate the concentration of Ni2+ in a solution that was prepared by mixing 40.00 mL of 0.0400M…
A: Given data: Volume of Ni2+ = 40 mL Concentration of Ni2+ = 0.04 M Volume of EDTA = 30 mL…
Q: The Cr plating on a surface that measured 3.00 cm x 4.00 cm was dissolved in HCl. The pH was…
A: Given : molarity of EDTA : 0.01441M Volume of EDTA = 10.19mL Total amount of EDTA or milimole of…
Q: . A 50.00 mL solution containing Ni2+ and Fe2+ was treated EDTA to bind all the metal ions. After…
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Q: A 25.0 mL aliquot of 0.0660 M EDTA was added to a 46.0 mL solution containing an unknown…
A: Total concentration of EDTA = 0.0660 M Volume of EDTA = 25 mL EDTA reacts with V3+ and Ga3+
Q: A 60.00 mL of buffered solution (pH 10) containing Zn2* and Ni2* ions (from a chip sample) is…
A: Metal ion combine with EDTA in 1 : 1 mole ratio. So we would calculate moles of both metal ions…
Q: If you have a sample of 100 mg/L of calcium, and you have two standardized EDTA solutions of 0.005 M…
A: the balanced equation for the reaction between EDTA and Ca is Ca+2 + EDTA–4 ----------->…
Q: Standard CaCO, is used to standardize the EDTA solution prior to titration. Suppose 0.385 g of CaCO,…
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Q: Titration of Ca2+ and Mg2+ in a 50.00 mL sample of hard water required 23.65 mL of 0.01205 M EDTA. A…
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Q: 0.5 mg sample required 20.5 ml. EDTA for titration. The EDTA was standardized by titrating 25 ml. of…
A: The question is based on the concept of complexometric titration. we have to analyse the alumina…
Q: Chromium (III) ion was complexed with EDTA and determined via back-titration. Given the following…
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Q: What is the value of pMg for 50.0 ml of a 0.0500 M Mg*2 solution buffered at pH 10.00 and titrated…
A: Question is based on the concept of quantitative analysis. We have to calculate P value of magnesium…
Q: What is the value of pMg for 50.0 ml of a 0.0500 M Mg*2 solution buffered at pH 10.00 and titrated…
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Q: A solution was prepared by dissolving about 30.00m g of EDTA in approximately 1 L of water and…
A: The solution is given below -
Q: A 25.00 mL sample containing Fe3+ was treated with 10.00 mL of 0.03676 M EDTA to complex all the…
A: A 25.00 mL sample containing Fe3+ was treated with 10.00 mL of 0.03676 M EDTA to complex all the…
Q: A 100, 0mL containing Zn^ 2+ was treated with 50.0 of 0.0500 M EDTA complex all the Zn^ 2+ and leave…
A: We have given that 100mL containing Zn2+ was treated with 50.0ml of 0.0500 M EDTA complex excess…
Q: Calculate pMn when 50.00 ml. of 0.100 0 M Mn is titrated with 25.00 ml. of 0.200 0 M EDTA. The…
A: The balanced equation for the reaction between Mn2+(aq) and EDTA, Y4-(aq) is: Mn2+(aq) + Y4-(aq) ⇌…
Q: . The Tl in a 9.57 g sample of rodenticide was oxidized to the trivalent state and treated with an…
A: The question is based on the concept of quantitative analysis. We have to quantitatively estimate…
Q: For the titration of 20.0 mL of 0.0100 M EDTA with 50.0 mL of 0.0200 M MNPO4 at pH = 10.00,…
A: The given information is: Volume of EDTA = 20.0ml Molarity of EDTA= 0.010 M Volume of MnPO4 = 50.0ml…
Q: Calculate the pZn2+ for solutions prepared by adding 0.00, 5.00, 10.00, 15.00, 20.00, 25.00 and…
A: The concentration of Zn2+ can be determined as: M1V1(Zn2+)=M2V2(EDTA) pZn2+ can be determined by:…
Q: The following data were obtained from the spectrophotometric titration of Cu(II) and Ca(II) in an…
A: One mole of oxygen atoms contains 6.02214179×10236.02214179×1023 oxygen atoms. Also, one mole of…
Q: In the analysis for total hardness, formation of Ca-EDTA complex in the presence of an…
A: The three equilibrium constants are given KCa-EDTA , KMg-EDTA , KMg-Ind for the complex formations…
Q: An EDTA solution was allowed to react with Pb²⁺ to produce 0.25 M PbY²⁻, 2.67×10⁻⁸ M Pb²⁺ and an…
A: The reaction is: Pb2++EDTA⇔PbY2-
Q: A water sample was tested for water hardness. A 50.00 mL sample, prepared and buffered to pH 10,…
A: a. At the pH = 10, EDTA form complex with both Ca2+ and Mg2+ ion and the total hardness of water is…
Q: 3. A solution contains 1.694 mg of CoSo. (155.0 g/mol) per milliliter. a. Calculate the volume of…
A: a) Amount of CoSO4 = 1.694 mg/mL Calculation of mass of CoSO4: Mass=1.694 mg mL-1×25 mL=42.35 mg…
Q: A cyanide solution with a volume of 12.99 ml was treated with 30.00 mL. of Ni solution (containing…
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Q: A 1.509-g samle of a Pb/Cd alloy was dissolved in acid and diluted to exactly 250.0 mL in a…
A: The explanation is given below-
Q: You are asked to titrate a Mn3+ solution with EDTA at pH 9.00. The overall ionic strength of the…
A: Given- Log k = 25.2k =1025.2now αEDTA4-=5.4 ×10-2×1025.2 (a).k'(conditional formation constant…
Q: A water sample was tested for water hardness. A 50.00 mL sample, prepared and buffered to pH 10,…
A: Calculate number of moles of EDTA: 1 mL = 0.001 L No.of moles=Molarity×Volume…
Q: A standard solution of EDTA (0.08 M) is being used to titrate 50 ml of a 0.04 M Ca 2+ solution.…
A: Q.1: Before the addition of EDTA solution, [Ca2+] = 0.04 M pCa2+ = - log[Ca2+] = - log(0.04) =…
Q: How do I find Moles of EDTA required for a complexometric titration of Magnesium if I have the…
A: Molarity is defined as “the number of moles of solute present in per litre of solution”. It is…
Q: In a solution kept constant by buffering to pH= 8.0, 50.0 mL of 0.0050 M Ni2+ is 0,0100 İn titration…
A: The question is based on the concept of quantitative analysis. We have to calculate pNi at different…
Q: The cadmium and lead ions in a 50.00 mL sample required 40.09 mL of a 0.005000 M EDTA for titration.…
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Q: chip sample) is analyzed using EDTA titration with EBT as indicator. The following data were…
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Q: In a solution kept constant by buffering to pH= 8.0, 50.0 mL of 0.0050M Ni2+ is 0,0100 In titration…
A: The question is based on the concept of complexometric titrations. We have to calculate pNi at…
Q: What is the value of pMg for 50.0 ml of a 0.0500 M Mg2 solution buffered at pH 10.00 and titrated…
A: The question is based on the concept of complexometric titration. We have to calculate P value of…
Q: If the water sample used for titration was buffered with acid instead of alkali, the amount of EDTA…
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Q: A 25.0 mL aliquot of 0.0700 M EDTA was added to a 32.0 mL solution containing an unknown…
A: Interpretation - The original concentration of the V3+ solution is to be explained. Given…
Q: 50 mL of a solution of 0.0200 M Zn2+ will be titrated with 0.0100 M EDTA in 0.0100 M NH3 at pH…
A: given values = K1 = 1.02 x 10-2, K2= 2.14 x 10-3, K3 = 6.92 x 10-7 and K4 = 5.50 x 10-11. pH = 6.0
Q: A 1.000 ml aliquot of a solution containing Cu* and Ni* is treated with 25.00 mL of a 0.03468 M EDTA…
A: EDTA is Ethylenediamine tetra acetic acid which is used as a chelating ligand. The balanced chemical…
Q: Titration of Ca2+ and Mg2+ in a 50.00 mL sample of hard water required 23.65 mL of 0.01205 M EDTA. A…
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Solved in 2 steps
- A solution was prepared by dissolving about 30.00m g of EDTA in approximately 1 L of water and standardizing against 50.00-mL aliquots of 0.004356 M Mg2+. An average titration of 32.65 mL was required. Calculate the molar concentration of the EDTA.At pH 7, what metal ions can be titrated by EDTA?What is the equivalence volume when 0.0500 M EDTA is titrated with 100.0 mL of 0.0500 M Mn+ buffered to a pH of 9.00?
- b. EDTA cannot be used as a primary standard always. When can EDTA be used as a primarystandard ? Give reason why EDTA is used in complexometric titrations.Calculate the % Copper in the alloy using the average titration vallue. given:Devarda alloy= 0.518g [EDTA] = 0.02 mol•dm^3 average titration number= 6.84cm^3Compare the two quantities based on the given condition. Titration of the same sample solution of MgCl2 I. Volume at EP with 0.10 M EDTA as titrant II. Volume at EP with 0.10 M AgNO3 as titrant Are they equal? Or which one is greater? Or can it be determined?
- A 0.1021 g sample containing ZnO was titrated using a standard EDTA solution with Erichrome Black T as an indicator. It took 25.52 mL of 0.0100 M EDTA to reach the endpoint. What is the percentage of ZnO in the sample?An EDTA solution was allowed to react with Pb²⁺ to produce 0.25 M PbY²⁻, 2.67×10⁻⁸ M Pb²⁺ and an excess of 0.10 M at equilibrium (K = 1.1×10⁸). What will be the hydronium ion concentration of the resulting solution?For complexometric titration of Ca (II) ions in the shell of an egg sample weighing 59,427 g, the necessary processes were applied to the egg shells and a sample of 100 mL was prepared. From the prepared sample, 1 mL was taken and diluted to 100 mL, the pH was adjusted, and two drops of EBT indicator were dripped on it. The prepared solution was titrated with 27.4 mL of EDTA solution set at 0.0097 M. Calculate the amount of calcium in the sample in CaCO3%. (Ca = 40g / mol, CaCO3= 100g / mol)
- Chromel is an alloy composed of nickel, iron and chromium.A 0.6472 g sample was dissolved and diluted to 250 mL. When a50 mL aliquot of 0.05182 M EDTA was mixed with an equal volumeof the diluted sample and all the three ions were chelated, a 5.11 mLback titration with 0.06241 M copper (II) was required.The chromium in a second 50 mL aliquot was masked through theaddition of hexamethylenetetramine, titration of the Fe and Nirequired 36.28 mL of 0.05182 M EDTA.Iron and chromium were masked with pyrophosphate in a third50 mL aliquot and the nickel was titrated with 25.91 mL of theEDTA solution.Calculate the percentage of nickel, chromium and iron in thealloy.Calculate the concentration of Ni2+ in a solution that was prepared by mixing 40.00 mL of 0.0400M Ni2+ with 30.00 mL of 0.0600M EDTA. The mixture was buffered to a pH of 6.0.A 60.00 mL of buffered solution (pH 10) containing Zn and Nit ions (from a chip sample) is analyzed using EDTA titration with EBT as indicator. The following data were recorded: M of EDTA = 0.05204 V of EDTA for Zn2+ =D41.97 V of EDTA for Ni2+ mL = 15.16 mL How many mmoles of Zn and Ni were present in the solution? If the weight of the chip is 1.000 g, give the % Zn and % Ni in the original sample.