52. ||| An 80 kg construction worker sits down 2.0 m from the end of a 1450 kg steel beam to eat his lunch, as shown in Figure P8.52 D. The cable supporting the beam is rated at 15,000 N. Should the worker be worried?
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After solving the problem also determine the normal and frictional forces at the left end of the beam.
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- A simply supported beam, having the following properties: 5.5 m length, Mcr = 30 kN-m, Ig = 7000x10^6 mm^4, Icr = 3000x10^6 mm^4, uniformly distributed dead load = 5 kN/m, uniformly distributed live load = 7 kN/m, Ec = 21,000 MPa. b) Determine the computed value of Ie (DL+LL).An industrial equipment manufacturing factory needs a 1.5m long shaft that can deliver 75kW @ 600rpm. The design concept will consider factor of safety of 2.5. Both solid & hollow shafts are considered. For hollow shaft, outside-to-inside diameter ratio is 6:5. Material considerations are as tabulated: Properties Solid shaft Hollow shaft Max. torsional strength 240MPa 200MPa Max. angular deflection 3.5° 2.5° Modulus of rigidity 83GPa 83GPa Material density 7,200kg/m3 7,200kg/m3 Material cost P82.00/kg P135. 00/kg Compute the most economic design of shaft which conforms to customer’s requirement.The doubly-symmetric beam cross section shown in Figure P12.3b has been proposed fora short foot bridge. The cross section will consist of two identical steel pipes that are securelywelded to a steel web plate that has a thickness of t = 9.5 mm. Each pipe has an outside diameterof d = 70 mm and a wall thickness is 5 mm. The distance between the centers of the two pipes ish = 370 mm. Internal forces of P = 13 kN, V = 25 kN, and M = 9 kN·m act in the directionsshown in Figure P12.3a. Determine the stresses acting on horizontal and vertical planes:(a) at point H, which is located at a distance of yH = 120 mm above the z centroidal axis.(b) at point K, which is located at a distance of yK = 80 mm below the z centroidal axis.Show the stresses on a stress element for each point.
- The doubly-symmetric beam cross section shown in Figure P12.3b has been proposed fora short foot bridge. The cross section will consist of two identical steel pipes that are securelywelded to a steel web plate that has a thickness of t = 9.5 mm. Each pipe has an outside diameterof d = 70 mm and a wall thickness is 5 mm. The distance between the centers of the two pipes ish = 370 mm. Internal forces of P = 13 kN, V = 25 kN, and M = 9 kN·m act in the directionsshown in Figure P12.3a. Determine the stresses acting on horizontal and vertical planes:(a) at point H, which is located at a distance of yH = 120 mm above the z centroidal axis.(b) at point K, which is located at a distance of yK = 80 mm below the z centroidal axis.Show the stresses on a stress element for each point.FIGURE P12.3a FIGURE P12.3bP12.5 An extruded polymer flexural member is subjected to an internal axial force of P = 580 lb,an internal shear force of V = 420 lb, and an internal bending moment of M = 6,400 lb·in.,…Given the following properties of bridge deck girder: Barrier Weight, BW = 7.3kN/m Future wearing surface load = 1.20 kPa, Span length, L=12.0 m, Load of stay-in-place metal forms, wsmf=0.335kPa Unit wt of concrete, wc=23.54 kN/m³ Slab thickness = 200mm. •Determine the shear and moment per interior girder due to Dead Load, DC. •Determine the shear and moment per interior girder due to Dead Load, DW.Calculate the support reaction force for the uniformly distributed load below, where w=w= 27 N/m and LAB=LAB= 4 m. The downward direction is denoted as positive direction.
- Two shafts, one solid the other one hollow, are connected end to end by meansof a coupling in which there are 8 screws on the pitch diameter D = 250 mm.The solid shaft has diameter d = 50 mm and transfers the power P = 500 kW at 75 rev/s.The external diameter of the hollow shaft is dex = 75 mm.Note: All parts of the system must be equally strong, and able to transfer the requiredpowerCalculate:(a) The internal diameter di of the hollow shaft(b) The diameter of the bolts db connecting the two shafts(c) If the hollow shaft has to be replaced by a rectangular hollow cross-section withouter dimensions b x h and uniform wall thickness of 4 mm.Calculate the values b, h while following the request to keep h = 2b(10) A weight of 270kg falls a distance of 1.0m & strikes a coil compression spring which absorbs the blow with a deflection of 0.3m. The mean diameter of the coils is to be 8x the wire diameter. If the allowable stress is 415MPa & the modulus of rigidity is 80GPa, find the diameter of the wire & the number of effective coils required.1) A flange coupling connects two 50mm shafts. The flanges are fitted with 4 bolts of SAE1040 steel on an 80mm bolt circle. The shaft runs @ 360 rpm & transmits 30kW. Assume a factor of safety 4, ultimate tension of 490x103 kPa; ultimate shear of 400x103 kPa, determine: (a) the torque transmitted in kN-m; (b) the minimum diameter of the bolts required based on commercial sizes; (c) the minimum thickness of the flange.
- In the figure below, suppose that Fw = 40 N. What is the value of FT1 (tension 1)? Consider that the ropes are massless and unstretchable. a. 28 N b. 31 N c. 34 N d. 52 B e. 58 NA generator driven by a wind turbine is required to deliver 5 MW of power at the generator terminals. The turbine is a two-blade propeller rotating about a horizontal axis and the maximum permitted shear stress of the turbine shaft is 55x106 N/m2 The rotor is designed to operate at a rotational speed of 45 revolution per seconds .The stage efficiencies are Cp 0.32, ngb = 0.90, ng = 0.92. %3D . (i) If the turbine delivers its rated power at a wind average speed of 22 m/s, calculate the corresponding diameter of the propeller and its TSR, assuming a typical value for the overall efficiency. The air density may be assumed to have a value 1.29 kg/m³. (ii) Calculate the torque on the turbine shaft.a. An overhead line has the following data: Span length= 160 m Conductor diameter= 0.95 cm Weight per unit length of the conductor= 0.65 kg/m Ultimate stress= 4,250 kg/cm2 Wind pressure= 40 kg/m2 Safety factor= 5 Calculate the sag? b. Derive the expression for the lowest point of the catenary curve if the supports are at different levels. Given that weight of conductor= 0.35 kg/m. Maximum allowable tension= 800 kg. Span length= 160 m and safety factor = 2. Find minimum point of catenary if supports are at 70 m and 60 m.