57. What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 43.88 mL of a 0.3842 M solution of Cu(NO3)2? 2Cu(NO3)2 + 4KI → 2Cul + 12 + 4KNO,

Chemistry: Principles and Reactions
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ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter3: Mass Relations In Chemistry; Stoichiometry
Section: Chapter Questions
Problem 24QAP: Twenty-five mL of a 0.388 M solution of Na2SO4 is mixed with 35.3 mL of 0.229 M Na2SO4. What is the...
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57. What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 43.88 mL of
a 0.3842 M solution of Cu(NO3)2?
2Cu(NO3)2 + 4KI → 2Cul + I2 + 4KNO,
Transcribed Image Text:57. What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 43.88 mL of a 0.3842 M solution of Cu(NO3)2? 2Cu(NO3)2 + 4KI → 2Cul + I2 + 4KNO,
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