6) A particular reaction has the following rate constant at different temperatures:Temperature (°C)k (s¹)Temperature (K)1/T (K)6.78 x 10-40.134-5233a. Convert the temperature to kelvin, find 1/T (K), and take the natural log of the rate constant and complete thechart above.In (k)b. Plot 1/T (K) in the x-axis and In (k) in the y-axis. This is the linear form of the Arrhenius Equation.C. Find the slope of the line and then calculate the activation energy of the reaction.d. Use the 2-point Arrhenius Equation to find the rate constant at T = 0 °C.

Answered: 6) A particular reaction has the…

Chemistry & Chemical Reactivity

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ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter14: Chemical Kinetics: The Rates Of Chemical Reactions

Section: Chapter Questions

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Question

6) A particular reaction has the following rate constant at different temperatures:
Temperature (°C)
k (s¹)
Temperature (K)
1/T (K)
6.78 x 10-4
0.134
-52
33
a. Convert the temperature to kelvin, find 1/T (K), and take the natural log of the rate constant and complete the
chart above.
In (k)
b. Plot 1/T (K) in the x-axis and In (k) in the y-axis. This is the linear form of the Arrhenius Equation.
C. Find the slope of the line and then calculate the activation energy of the reaction.
d. Use the 2-point Arrhenius Equation to find the rate constant at T = 0 °C.

Expert Solution

Step 1

We now the Arrhenius equation for activation energy determination.

ln(k₂/k₁) = E_a/R x (1/T₁ - 1/T₂)

where,

E_a = the activation energy of the reaction in J/mol
R = the ideal gas constant = 8.3145 J/K·mol
T₁ and T₂ = absolute temperatures (in Kelvin)
k₁ and k₂ = the reaction rate constants at T₁ and T₂

So it is very important equation for activation energy determination

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