6. Riboswitches are RNA sequences found in the 5' untranslated region of messenger RNA (mRNA) that control gene expression in response to small molecule binding. These regulatory elements adopt two conformations: an "on" state when a specific small molecule ligand is bound and an "off" state in the absence of ligand. When the mRNA is "off", the gene remains untranslated. The structure of a guanine-responsive riboswitch was solved in 2004 (Nature, 432, 411-415) and is shown below at low (left) and high (right) resolution with a guanine derivative bound: (see Blackboard for color image) Guanine riboswitch with a guanine derivative (red) bound; zoomed out. U22 U47 HX C74 U51 Guanine riboswitch with a guanine derivative (HX) bound; atomic detail. Note: blue = nitrogen, red = oxygen. C and U follow standard nucleotide naming conventions. a. What interactions are occurring between the riboswitch and the guanine derivative that make binding favorable? b. Of these interactions, which ones confer specificity for the riboswitch binding guanine and not the other nucleobases (C, A, T, U)?

6. Riboswitches are RNA sequences found in the 5' untranslated region of messenger RNA (mRNA) that control gene expression in response to small molecule binding. These regulatory elements adopt two conformations: an "on" state when a specific small molecule ligand is bound and an "off" state in the absence of ligand. When the mRNA is "off", the gene remains untranslated. The structure of a guanine-responsive riboswitch was solved in 2004 (Nature, 432, 411-415) and is shown below at low (left) and high (right) resolution with a guanine derivative bound: (see Blackboard for color image) Guanine riboswitch with a guanine derivative (red) bound; zoomed out. U22 U47 HX C74 U51 Guanine riboswitch with a guanine derivative (HX) bound; atomic detail. Note: blue = nitrogen, red = oxygen. C and U follow standard nucleotide naming conventions. a. What interactions are occurring between the riboswitch and the guanine derivative that make binding favorable? b. Of these interactions, which ones confer specificity for the riboswitch binding guanine and not the other nucleobases (C, A, T, U)?

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter15: From Dna To Protein

Section: Chapter Questions

Problem 10TYK: A part of an mRNA molecule with the sequence 5-UGC GCA-3 is being translated by a ribosome. The...

See similar textbooks

Similar questions

1.List three different mRNA sequences that could encode the amino acid sequence histidyl-alanyl-arginyl-seryl-leucyl-valyl-cysteine.
7. A segment of a DNA strand consists of ...GCTTAGACCTGA.... (a) Identify the expected nucleotide order in the complementary mRNA (b) Identify the sequence of amino acids coded for by this segment of DNA. (c) Describe the bond that forms during translation to link amino acids together. Identify the functional groups that react and the atoms involved.
1.The Shine Dalgarno sequence is ____________. located in the 50S subunit of ribosome. located on the 16S rRNA component of the 30S subunit of ribosome. a sequence upstream of the AUG initiation codon on mRNA. a DNA consensus sequence in the promoter region of a gene. a signal for transcription termination.
1) Below are some events that occur in the process of translating mRNA into a protein in a bacterial cell. Pick the best order of events. EF-G–GTP binds to the tRNA in the A site and causes the tRNA to advance to the P site.- The rRNA in the ribosomal 30S subunit base-pairs with the Shine-Dalgarno sequence in the mRNA.- Peptide bond forms between the growing amino acid chain in the P site and the new amino acid in the A site.- IF-3 binds in the E site.- RRF binds in the A site.- RF-1 or -2 binds in the A site.- Ribosomal complex dissociates.- Peptide chain dissociates from final tRNA.- fMET tRNA binds to the start codon in the mRNA.- RF-3–GTP causes displacement of RF-1 or -2 and its exit from the ribosome.- EF-G–GTP binds to the A site and causes RRF to shift to the P site.- A conformational change in the 30S subunit allows the 50S subunit to bind, forming the 70S ribosome. Step 1, 2, 3, 4 ,5 ,6 , 7, 8, 9, 10, 11, 12
4. Gene expression in mammals can be increased by which of the following mechanisms? A. X-chromosome inactivation (as in the case of the female tortoiseshell cat) B. histone demethylation C. histone methylation D. histone deacetylation E. histone dephosphorylation 5. Which of the following DNA components is found on the exterior of this double-stranded molecule? A. the nitrogenous bases B. the pyrimidine bases C. the ribose sugars D. the purine bases E. the phosphates
4) Shown below is a schematic drawing of a gene, with the transcription unit divided into numbered regions. The arrows indicate transcription initiation sites, "D" indicates a splice donor site, "A" indicates a splice acceptor site, and "An" indicates a polyadenylation signal. Indicate all the possible mRNAs that could be produced from this gene (you don't need to draw new schematics - just list the regions that would be included in each mRNA by number)
3’ G G A U A C G U C A C C G G U A U A A G G U U U C G U A U C G 5’ If the RNA synthesized above is a functional mRNA and all the nucleotides belong to an exon, a. how many codons are present in this mRNA? b. how many codons actually code for a protein in this mRNA? c. what stop codon is present in this mRNA?
1. Which of the following statements about mRNA is correct?a. Eukaryotic mRNA is generally polycistronic while prokaryotic mRNA is monocistronic.b. Both prokaryotic and eukaryotic RNA is polycistronic.c. Both prokaryotic and eukaryotic RNA is monocistronic.d. Eukaryotic mRNA is generally monocistronic while prokaryotic mRNA is polycistronic. 2. Which of the following statements about leading and lagging strand synthesis is correct?a. The lagging strand can only be synthesized once the leading strand has been completedb. Lagging strand is synthesized is continuously while leading strand is synthesized fragment by fragment.c. Leading strand is synthesized is continuously while lagging strand is synthesized fragment by fragment.d. Okazaki fragments are used to synthesize the leading and lagging strands of DNA. 3. An intron of a gene had a G to T mutation on the 3’ splice site. What will happento this intron?a. The intron will not be spliced out but will not be recognized in the ribosome…
2a) Suppose you have a gene in which a single base substitution has created the nonsense mutation 5'TAA3' (which will be transcribed into 5'UAA3' in the mRNA - but recall that mutations are changes in the DNA sequence). Name all the amino acids that could have been coded for by the original, unmutated codon at that position in the gene.
1. The poly A tail of an mRNA molecule was removed by a deadenylase enzyme before it is recognized by the ribosomes. What will happen to this mRNA? a. It will not be translated anymore and will be degraded. b. It will get stuck in the small ribosomes since it will be difficult to set the proper start site. c. The reading frame of translation will change. d.The mRNA will be bound by the ribosomes for translation. 2. Which of the following is true regarding these DNA repair mechanisms? a. Non-homologous end joining is less likely to produce mutations than homologous recombination. b. Errors during DNA synthesis that are not caught by the replication machinery can be corrected by mismatch repair. c. DNA damage from chemical reactions cannot be undone. d. Proofreading from DNA polymerase I reduces the error rate in DNA to about 1 in 100 nucleotides. 3. Which of the following enzymes involved in DNA replication correctly pairs with its function? a. Helicase seals gaps between DNA…
1. A region of DNA in a particular cell synthesizes a segment of RNA that is 174 bases long and in the form of a large palindrome. The RNA is transported to the cytoplasm and folds into a hairpin loop of double stranded RNA. In the cytoplasm, the hairpin loop is recognized by a double-stranded RNA cutting enzyme (dicer) and is cut into 21 BP lengths. When these 21 BP double stranded segments are combined with protein, they function by: Answer choices destroying specific mRNAs priming the synthesis of DNA sequences adding DNA to the chromosome ends (telomeres) acting as decoys for RNA degrading enzymes thus protecting the mRNAs present splicing the introns out of messenger RNA 2. The following are genotypes of merozygotes of E. coli with various combinations of lac operon mutations. Determine the phenotype with respect to beta-galactosidase (z), permease (y), and trans-acetylase (a) of each combination as U = uninducible, I = inducible, and C = constitutive. Choose from…
1. What would be the amino acid sequence encoded by the mRNA5' C C A U G A C G U C G G A U C A A U G A G C 3' 2. If the nucleotide bolded and underlined in red in part 1 changes from C to a G, what type of mutation would that be? 3. What would happen to the amino acid sequence if the C bolded in red in part 1 is changed to a G? 4. What would happen to the amino acid sequence if the C bolded in red is deleted?