6. The equation below shows the combustion of butane (C4H10). How many moles of water can be produced by 12.5 moles of C4H10 reacting with excess oxygen? 2C4H10 + 1302 --> 8CO2 + 10H2O (Hint: 1 step conversion) * O 2.50 moles O 62.5 moles ) 125 moles O 202 moles

General, Organic, and Biological Chemistry
7th Edition
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:H. Stephen Stoker
Chapter6: Chemical Calculations: Formula Masses, Moles, And Chemical Equations
Section: Chapter Questions
Problem 6.68EP: How many carbon monoxide molecules (CO) are needed to react with 8 hydrogen molecules (H2) to...
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6. The equation below shows the combustion of butane (C4H10). How many
moles of water can be produced by 12.5 moles of C4H10 reacting with excess
oxygen? 2C4H10 + 1302 --> 8CO2 + 10H2O (Hint: 1 step conversion) *
ーーン
O 2.50 moles
O 62.5 moles
) 125 moles
) 202 moles
Transcribed Image Text:google.com/forms/d/e/1FAlpQLSdURzeonPFwwoKyQMU_qctnfnz9K1exDoKPAKuowEwnv71LHQNIeW 6. The equation below shows the combustion of butane (C4H10). How many moles of water can be produced by 12.5 moles of C4H10 reacting with excess oxygen? 2C4H10 + 1302 --> 8CO2 + 10H2O (Hint: 1 step conversion) * ーーン O 2.50 moles O 62.5 moles ) 125 moles ) 202 moles
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