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- Table 1: Temp vs. solubility data of ammonium chloride. Test tube g NH4Cl/10 mL H2O Crystallization temp. (ºC) 1 1.0 g/10 mL H2O 10 oC 2 1.8 g/10 mL H2O 20 oC 3 2.9 g/10 mL H2O 40 oC 4 3.8 g/10 mL H2O 65 oC 5 4.4 g/10 mL H2O 95 oC Use the table to plot a solubility curve for ammonium chloride on the graph provided below. For the best fit line, use a smooth curve. "Mass of Solute per 100 mL of H2O," should be written on the y-axis (use increments of 2g for every box). "Temperature (°C)" should be written on the x-axis (use increments of 10 °C for every 2 boxes).Concentration of iodide solution (mM) 100.0 Search And Select Concentration of thiosulfate solution (mM) 22.8 Concentration of hydrogen peroxide solution (mM 176.0 Temperature of iodide solution (\deg C) 25.0 Volume of iodide solution (1) used (mL) 10.0 Volume of thiosulfate solution (S2032-) used (mL) 1.0 Volume of DI water used (mL) 2.5 Volume of hydrogen peroxide solution (H2O2) used (mL) 7.5 Time (s) 12.8 What is the Initial concentration of hydrogen peroxide in reaction ( mM)?If 500mL of 0.10M Ca2+ is mixed with 500mL of 0.10M SO42-, what mass of calcium sulfate will precipitate? Ksp for CaSO4 is 2.40 • 10-5. express answer to 3 significant figures. And include units.
- It is known that acid content has a major effect on theflavor of vinegars, but most cheaper vinegars are diluted similarly to 5% acidity Wt./vol. % is equivalent to gsolute per 100mL solution (so 5% is equivalent to 5 g acid/100 mL solution). a.) First, calculate the approximate molar concentration of acetic acid in the 5% wt./vol vinegar. b.) Next, calculate the expected molarity of acetic acid in the solution upon dilution by a factor of 5. Thank you!KNO3 (aq) added to CaC2O4 (Ksp = 1.3 x 10-8) in solution will lead to __________ in solubility of the solid no effect then decrease increase no effectBen prepared a salicylic acid in pentanol solution by adding 4.77 g of salicylic acid to 91.88 mL of pentanol. Calculate the mole fraction of salicylic acid in this solution. MW of salicylic acid= 138.12 g/mol MW of pentanol= 88.15 g/mol Density of pentanol= 0.8144 g/mL
- The following evidence was obtained from an experiment to determine the solubility of calcium chloride at room temperature. A sample of saturated calcium chloride solution was evaporated to dryness, and the mass of solid residue was measured.EvidenceVolume of solution (mL) = 15.0Mass of empty beaker (g) = 90.54Mass of beaker and residue (g) = 101.36The solubility of calcium chloride is g/100 mLMixing 150.0 mL of 1.50 M Ba(NO3)2 (aq) with 250.0 ml of 5x10-2M Na2SO4 at 25°C. The Ksp of barium sulfate is 1.08x10-10M2 at 298 K. What is the final concentration of barium ion in the solution.Calculate either [H3O+][H3O+] or [OH−][OH−] for each of the solutions at 25 °C.25 °C. Solution A: [OH−]=2.25×10−7 MSolution A: [OH−]=2.25×10−7 M Solution A: [H3O+]=Solution A: [H3O+]= MM Solution B: [H3O+]=9.29×10−9 MSolution B: [H3O+]=9.29×10−9 M Solution B: [OH−]=Solution B: [OH−]= MM Solution C: [H3O+]=0.000649 MSolution C: [H3O+]=0.000649 M Solution C: [OH−]=Solution C: [OH−]= M
- Submit a clean, dry, and properly labeled 50-mL reagent bottle for your unknown solution. Pipet 20.00 mL of the sample in 250-mL Erlenmeyer flask. Add 5 mL of buffer and 5 drops of indicator. Titrate the solution until it turns light blue. If the titration consumes more than 50 mL of the titrant, dilute the sample accordingly. Compute for ppm of CaCO3 using the following table. Mean Molarity = 2.487 x 10^-3 MBlank correction = 0.015 Formula = V (mL) titrant x Mean Molarity of Titrant x Molecular weight of CaCO3 x 1/V (L) sampleA solution is prepared by dissolving 40.00 g of NaCl (f.w. = 58.44 g mol–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol–1) to result in exactly 1 L of solution at 25 °C. Assume the density of the solution is that of pure water (dsolution = 1.000 g mL–1). The ebullioscopic constant (Kb) for water is 0.513 °C m–1. The cryoscopic constant (Kf) for water is 1.86 °C m–1. The vapor pressure of pure water is 0.0313 atm. Find the freezing point of the solution(in C to 2 decimal places)A solution is prepared by dissolving 40.00 g of NaCl (f.w. = 58.44 g mol–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol–1) to result in exactly 1 L of solution at 25 °C. Assume the density of the solution is that of pure water (dsolution = 1.000 g mL–1). The ebullioscopic constant (Kb) for water is 0.513 °C m–1. The cryoscopic constant (Kf) for water is 1.86 °C m–1. The vapor pressure of pure water is 0.0313 atm. Find the osmotic pressure in atm to three decimal places
