7. For the flow of a thin layer of liquid down an inclined planeshown:a. Using the cross-hatched element and through a force balance,velocityshowthatthedistribution across the layer is:dxy sin 0(b² – s? )2 µu =FreeSurfacean expression for thetheb. Derivet dxliquid velocitysurface.atfreeFixedYs dxc. Derivedischarge per unit width.d. Deriveanexpression for theWallbanexpression for theshear stress at the fixed wall.

Answered: Image /qna-images/answer/9ee0d9f0-7a8b-4a01-b4fe-8fe9e4d4a440.jpg

7. For the flow of a thin layer of liquid down an inclined plane shown: a. Using the cross-hatched element and through a force balance, show that the velocity distribution across the layer is: dx y sin 0 и %3 (b² – s² ) Free 2 µ Surface b. Derive an expression for the liquid velocity surface. at the free t dx Y s dx Fixed c. Derive an expression for the discharge per unit width. d. Derive an expression for the shear stress at the fixed wall. Wall

7. For the flow of a thin layer of liquid down an inclined plane shown: a. Using the cross-hatched element and through a force balance, show that the velocity distribution across the layer is: dx y sin 0 и %3 (b² – s² ) Free 2 µ Surface b. Derive an expression for the liquid velocity surface. at the free t dx Y s dx Fixed c. Derive an expression for the discharge per unit width. d. Derive an expression for the shear stress at the fixed wall. Wall

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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