7.00 mL of 6.00 x 103 M Fe(NO3)3 (6.00 times 10 to the minus 3rd power MFe (NO3)3) is added to 4.00 mL of 8.00 x 10³ M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)2*] was found to be 1.00 x 103 M (1.00 times 10 to the minus 3rd power M) at equilibrium. How many initial moles of SCN° (SCN minus) are present in the solution? Express your answer as a decimal number (no exponents).

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter16: Applications Of Neutralization Titrations
Section: Chapter Questions
Problem 16.20QAP
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7.00 mL of 6.00 x 103 M
Fe(NO3)3 (6.00 times 10 to the minus
3rd power MFe (NO3)3) is added to
4.00 mL of 8.00 x 103 M KSCN
(8.00 times 10 to the minus 3rd power
M KSCN) along with 7.00 mL of water.
The concentration of [F e(SCN)2+] was
found to be 1.00 x 103 M (1.00 times
10 to the minus 3rd power M) at
equilibrium. How many initial moles of
SCN (SCN minus) are present in the
solution? Express your answer as a
decimal number (no exponents).
Your Answer:
Answer
units
Transcribed Image Text:7.00 mL of 6.00 x 103 M Fe(NO3)3 (6.00 times 10 to the minus 3rd power MFe (NO3)3) is added to 4.00 mL of 8.00 x 103 M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 103 M (1.00 times 10 to the minus 3rd power M) at equilibrium. How many initial moles of SCN (SCN minus) are present in the solution? Express your answer as a decimal number (no exponents). Your Answer: Answer units
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