8. Calculate the molarity of each of these solutions A 5.623 gram sample of sodium bicarbonate is dissolved in enough water to make 250.0 mL of solution b. A 184.6 mg sample of potassium dichromate is dissolved in enough water to make 500.0 mL of solution. c. A 16.45 gram sample of sodium chloride is dissolved in enough water to make 1.000L of solution d. A 853.5 mg sample of potassium iodate is dissolved in enough water to make 250.0 mL of solution a.

Introductory Chemistry For Today
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Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.23E
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8. A-D
8. Calculate the molarity of each of these solutions
A 5.623 gram sample of sodium bicarbonate is dissolved in enough water to
make 250.0 mL of solution
a.
b. A 184.6 mg sample of potassium dichromate is dissolved in enough water
to make 500.0 mL of solution.
A 16.45 gram sample of sodium chloride is dissolved in enough water to
make 1.000L of solution
d. A 853.5 mg sample of potassium iodate is dissolved in enough water to
make 250.0 mL of solution
с.
9.
Describe how
you
would
prepare
each of the following solutions
a. 250 mL of a 0.707 M sodium nitrate solution from 6.00 M stock solution.
b. 60.0 ml. of 0.200 M nitric acid solution from a stock solution of 4.00 M nitric
Transcribed Image Text:8. Calculate the molarity of each of these solutions A 5.623 gram sample of sodium bicarbonate is dissolved in enough water to make 250.0 mL of solution a. b. A 184.6 mg sample of potassium dichromate is dissolved in enough water to make 500.0 mL of solution. A 16.45 gram sample of sodium chloride is dissolved in enough water to make 1.000L of solution d. A 853.5 mg sample of potassium iodate is dissolved in enough water to make 250.0 mL of solution с. 9. Describe how you would prepare each of the following solutions a. 250 mL of a 0.707 M sodium nitrate solution from 6.00 M stock solution. b. 60.0 ml. of 0.200 M nitric acid solution from a stock solution of 4.00 M nitric
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