8. The trajectory of a projectile launched from ground is given by the equation y = -0.025 x? + 0.5 x where x and y are the coordinate of the projectile on a rectangular system of axes. Find the initial velocity and the angle at which the projectile is launched. Formula Vx = Vo cos 0 Vy = Vo sin 0 – gt x = Vo cos et y = Vo sin Ot-

8. The trajectory of a projectile launched from ground is given by the equation y = -0.025 x? + 0.5 x where x and y are the coordinate of the projectile on a rectangular system of axes. Find the initial velocity and the angle at which the projectile is launched. Formula Vx = Vo cos 0 Vy = Vo sin 0 – gt x = Vo cos et y = Vo sin Ot-

Name: 8. The trajectory of a projectile launched from ground is given by th
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: 8. The trajectory of a projectile launched from ground is given by the equationy = -0.025 x? + 0.5 xwhere x and y are the coordinate of the projectile on a rectangular system of axes. Findthe initial velocity and the angle at which the projectile is

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter3: Two-dimensional Kinematics

Section: Chapter Questions

Problem 48PE: Prove that the trajectory of a projectile is parabolic, having the form y=ax+bx2. To obtain this...

See similar textbooks

Similar questions

A catapult launches a rocket at an angle of 53.0 above the horizontal with an initial speed of 100 m/s. The rocket engine immediately starts a burn, and for 3.00 s the rocket moves along its initial line of motion with an acceleration of 30.0 m/s2. Then its engine fails, and the rocket proceeds to move in free fall. Find (a) the maximum altitude reached by the rocket, (b) its total time of flight, and (c) its horizontal range.
Prove that the trajectory of a projectile is parabolic, having the form y=ax+bx2. To obtain this expression, solve the equation x=v0xt for t and substitute it into the expression for y=v0yt(1/2)gt2 (These equations describe the x and y positions of a projectile that starts at the origin.) You should obtain an equation of the form y=ax+bx2 where a and b are constants.
A rocket is launched at an angle of 53.0 above the horizontal with an initial speed of 100. m/s. The rocket moves for 3.00 s along its initial line of motion with an acceleration of 30.0 m/s2. At this time, its engines fail and the rocket proceeds to move as a projectile. Find (a) the maximum altitude reached by the rocket, (b) its total time of flight, and (c) its horizontal range.
What do you need in order to determine the initial velocity of a projectile fired horizontally?
A projectile is projected with a velocity 9.8 m/s at 15° above the horizontal. What is the horizontal range of the projectile ? ( g = 9.8 m/s2)
A kicker hits the ball and the ball reaches the maximum height of 83.1 m and lands 10.7 seconds after being launched. Considering the ball as a projectile, calculate the ball's range if the launch angle is 66 degrees? Use g=9.80 m/s2
1. A golfer hits a golf ball on a flat, horizontal surface with an initial velocity of 67.7 m/s @ 45°. Calculate the following: (e) The range of the ball. (f) The position (x,y) of the ball at t=1.0s. (g) The components of velocity of the ball (Vx, Vy) at 1.0s. (h) The velocity vector of the ball at 1.0s. (i) The velocity vector of the ball just as it hits the ground.
A football is kicked at 25.0 m/s25.0 m/s at an angle of 27.0∘27.0∘ above the horizontal. Assume it starts 1.00 m1.00 m above ground level. (Neglect any effects due to air resistance.) Describe the velocity vector of the ball in terms of its ?-x- and ?-y-components, ??vx and ??vy, respectively, when it is 5.00 m5.00 m above ground level and still moving upward. Describe the velocity vector of the ball in terms of its magnitude ?v and angle ?θ above the horizon when it is 5.00 m5.00 m above ground level and still moving upward.
A baseball player hits a home run, and the ball lands in the left-field seats, y = 8.00 m above the point at which it was hit. It lands with a velocity of v = 37.0 m/s at an angle of 28o below the horizontal (see the Figure). The positive directions are upward and to the right in the drawing. Ignoring air resistance, find (a) the magnitude and (b) the direction of the initial velocity with which the ball leaves the bat.
The trajectory of a projectile launched from ground is given by the equationy = -0.035 x2 + 0.75 x, where x and y are the coordinate of the projectile on arectangular system of axes. Find the initial velocity and the angle at which theprojectile is launched.
1. AN ARROW IS SHOT AT 33 DEGREE ANGLE WITH HORIZONTAL. IT HAS A VELOCITY OF 25M/S. a. HOW HIGH WILL IT GO? b. WHAT HORIZONTAL DISTANCE WILL IT TRAVEL? c. TOTAL TIME IN AIR d. VELOCITY VECTOR AT MAX HEIGHT e. VELOCITY WHEN IT HITS THE GROUND
A cannonball is shot with an initial speed of 30.0 m/s and 25.0º angle below horizontal from a height of 12.0 m. How far can the cannonball go horizontally when it lands on the ground, in meters? Use g = 10.0 m/s2. (Hint: Clearly label quantities along x- and y- components and write down all steps.)