8.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 4.00 mL of 8.00 x 10-3 M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 4.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-4 M (2.00 times 10 to the minus 4th power M) at equilibrium.How many moles of F e3+ are present in the solution at equilibrium? Express your answer as a decimal number

8.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 4.00 mL of 8.00 x 10-3 M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 4.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-4 M (2.00 times 10 to the minus 4th power M) at equilibrium.How many moles of F e3+ are present in the solution at equilibrium? Express your answer as a decimal number

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter15: Molecular Luminescence Spectrometry

Section: Chapter Questions

Problem 15.10QAP

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A 5.00 mL tap water sample was measured out with a volumetric pipette, and added to a 25 mL Erlenmeyer flask. It was then titrated with a 0.0100 M Na2EDTA.2H2O solution, and found to take 0.635 mL of the EDTA solution to reach the blue endpoint.
8.00 mL of 9.00 x 10-3 M Fe(NO3)3 (9.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 5.00 mL of 5.00 x 10-3 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 6.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 10-4 M (1.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).
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1. How much volume (mL) is needed to standardize 0.05M of EDTA using 180mg of magnesium ribbon? MW: 24g/mol2. How many grams of EDTA is required to prepare 250mL of a 0.05M solution? MW: 292g/mol3. What is the Molarity of the EDTA solution if 35mL of the titrant was added to 0.2g of calcium carbonate? Round off to four decimal places
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9.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 5.00 mL of 4.00 x 10-3 M KSCN (4.00 times 10 to the minus 3rd power M KSCN) along with 6.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 10-3 M (2.00 times 10 to the minus 4th power M) at equilibrium.How many moles of F e3+ are present in the solution at equilibrium? Express your answer as a decimal number (no