A 50.00-mL aliquot of solution containing 0.358 of MgSO4 (FM 120.37) in 0.500 L required 38.08 mL of EDTA solution for titration. How many milligrams of CaCO3 (FM 100.09) will react with 1.00 mL of this EDTA solution?
Q: Calculate the molar concentration (and uncertainty) of an EDTA solution of which 5.40(±0.05) mL was…
A: Reaction taking place when CaCO3 is titrated with EDTA: Ca2+ + EDTA --------> Ca-EDTA complex
Q: A 50.00 mL sample of hard water is titrated with 0.0102 M EDTA solution (volume of blank titration=…
A: Given data,Volume of sample=50mLMolarity of EDTA=0.0102MVolume of EDTA=22.44mLVolume of EDTA for…
Q: 0.1500 g of an unknown sample was passed through a column of Amberlite IR-120(+) resin and titrated…
A:
Q: 50.0-mL sample containing Ni2+ was treated with 25.0 mL of 0.0500 M EDTA to complex all the Ni2+ and…
A:
Q: A 25.00 mL sample containing an unknown amount of A13+ and Pb2+ required 20.51 mL of 0.04633 M EDTA…
A:
Q: 0.5 mg sample required 20.5 ml. EDTA for titration. The EDTA was standardized by titrating 25 ml. of…
A: The question is based on the concept of complexometric titration. we have to analyse the alumina…
Q: 2+ Calculate the mass of Cu (At.wt. 63) that titrated iodometrically with I ,then the liberated I,…
A: Molarity = no. of moles/ vol (Lt)
Q: What is the value of pMg for 50.0 ml of a 0.0500 M Mg*2 solution buffered at pH 10.00 and titrated…
A: Question is based on the concept of quantitative analysis. We have to calculate P value of magnesium…
Q: A 50.00-mL aliquot of solution containing 0.395 of MgSO4 (FM 120.37) in 0.500 L required 39.55 mL of…
A:
Q: Write the involved chemical reactions for this: An EDTA solution was prepared by dissolving…
A:
Q: A solution containing 1.263 g of unknown potassium compound was dissolved in water and treated with…
A: Principle of atom conservation (POAC) method gives the idea of conservation of mass of an atom.…
Q: A phenol standard with a concentration of 4.00 ppm has an absorbance of 0.424 at a wavelength of 460…
A: PhOH std 4 ppm PhOH samp 0.269036 ppmA 0.424 aliquot 50 mLw 460 nm dilution 100 mLb 1 cm A 0.394c…
Q: A 25.00 mL sample containing Fe3+ was treated with 10.00 mL of 0.03676 M EDTA to complex all the…
A: A 25.00 mL sample containing Fe3+ was treated with 10.00 mL of 0.03676 M EDTA to complex all the…
Q: An eggshell is treated with NaOH to remove the membrane, dried and found to weigh 5.131 g. The shell…
A:
Q: To check the hardness of tap water by complexometric titration 50 mL of water sample is required for…
A:
Q: EDTA Titer A 500.0 mL standard solution of CaCO3 (1.93 g; FM = 100.09) was prepared. Calculate the…
A: Titer is the measure of concentration, defined as how many milligrams of reagent B will react with…
Q: A 100, 0mL containing Zn^ 2+ was treated with 50.0 of 0.0500 M EDTA complex all the Zn^ 2+ and leave…
A: We have given that 100mL containing Zn2+ was treated with 50.0ml of 0.0500 M EDTA complex excess…
Q: A 50.0 mL juice extract is colorimetrically assayed using Nelson's test. One milliliter (1.00 mL) of…
A: Given: 50 mL of original juice is used. 1 mL of the original solution is used to give absorbance of…
Q: A deepwell water sample of 100 mL was titrated with 0.010 M EDTA at pH 12 and consumed 31 mL.…
A:
Q: A river water sample was titrated against 0.0250 M EDTA to test its hardness. of 0.0250 M EDTA. A…
A: Here we have to determine the hard ness of river water in ppm from the following given data from…
Q: How many milliliters of 0.0300 M EDTA are required to react with 50.0 mL of 0.0120 M Cu2+? volume:…
A: The solution is given below -
Q: The following data were obtained from the spectrophotometric titration of Cu(II) and Ca(II) in an…
A: One mole of oxygen atoms contains 6.02214179×10236.02214179×1023 oxygen atoms. Also, one mole of…
Q: A 50.0 mL juice extract is colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL)…
A: We know that according to Beer-Lambert law, the absorbance of any solution is directly proportional…
Q: A 10.0 mL sample containing Fe³⁺ and Cu²⁺ was diluted to 100.0 mL solution. A 20.0 ml aliquot…
A: In EDTA titration, a masking agent is defined as a reagent that prevents one of the analyte from…
Q: A 25 ml solution of unkown containing Fe+3 and Ca+2 required 16.06 ml of 0.051 M EDTA for complete…
A: Back titration is a process where the unknown concentration of an analyte is determined by reacting…
Q: A 25.00-mL sample containing Fe31 was treated with 10.00 mL of 0.036 7 M EDTA to complex all the…
A: Given data,Volume of sample=25.0mL=0.025LTotal EDTA added=10.0mL=0.010LMolarity fo…
Q: A 50.0 mL aliquot of solution contairing 0.450 g of MgSO4 (FM 120.37) in 0.500L required 37.6 mL of…
A: EDTA titration :- It is a complexometric titrations . EDTA is short form of…
Q: C1. A carefully weighed 280mg Calcium carbonate was used in the standardization of an EDTA solution.…
A:
Q: A sample is analyzed for chloride by the Volhard method. Calculate the %KCl from the following data:…
A: Calculation of no. of mol of AgNO3: n=Molarity×Volume=0.1157 mol/L×35.00×10-3 L=4.0495×10-3 mol…
Q: A 50.0 mL juice extract is colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL) of…
A: Given: 50 mL of original juice is used. 1 mL of the original solution is used to give absorbance of…
Q: A 25.00 mL sample containing an unknown amount of Al3+ and Pb2+ required 19.13 mL of 0.04842 M EDTA…
A:
Q: What would your main concern be if you accidentally used wash buffer (10mM imidazole) instead of…
A: Answer is explained below. We know that, for binding to the metal-charged resin Imidazole competes…
Q: 3. A solution contains 1.694 mg of CoSo. (155.0 g/mol) per milliliter. a. Calculate the volume of…
A: a) Amount of CoSO4 = 1.694 mg/mL Calculation of mass of CoSO4: Mass=1.694 mg mL-1×25 mL=42.35 mg…
Q: A cyanide solution with a volume of 12.99 ml was treated with 30.00 mL. of Ni solution (containing…
A:
Q: Triplicate samples of NaOH was found to have concentrations of 0.1444 M (Trial 1), 0.1107 M (Trial…
A: Introduction : Titration can be defined as the technique where a solution of known concentration is…
Q: A 25.00-mL sample containing Fe3+ was treated with 10.00 mL of 0.036 7 M EDTA to complex all the…
A: In the question Following information given - Volume of Fe3+ Solution = 25 mL Volume of EDTA = 10 mL…
Q: Determination of water hardness using complexometric titration. During sample analysis (ppm…
A: Given: Determination of water hardness using complexometric titration. To determine EX…
Q: A 50.0 mL juice extract is colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL)…
A: Given: 50 mL of original juice is used. 1 mL of the original solution is used to give absorbance of…
Q: A total of 5 mL of blood samples were treated with trichloroacetic acid to precipitate proteins.…
A: Absorbance of blood sample = 0.502 Absorbance of 0.4 ppm standard = 0.396 Absorbance of 0.6 ppm…
Q: What is the function of masking agent in EDTA titration?
A: Masking may be defined as the process in which a substance, without any physical separation of it…
Q: What is the value of pMg for 50.0 ml of a 0.0500 M Mg2 solution buffered at pH 10.00 and titrated…
A: The question is based on the concept of complexometric titration. We have to calculate P value of…
Q: Chromel is an alloy composed of nickel, iron, and chromium. A 0.6418-g sample was dissolved and…
A: The 0.6418 g sample contains three metals: nickel, iron, and chromium. This total sample is…
Q: A 25.00 mL sample containing an unknown amount of Al and Pb* required 15.40 mL of 0.05788 M EDTA to…
A:
Q: How do you report the average and %RSD for the %w/w of acetic acid in an unknown solution after…
A: Acid-base titration:It is a method for determining the concentration of acid or base by neutrilizing…
Q: Given the following data during the potentiometric titration of 75.00 mL unknown NaCl solution by…
A:
Q: Water samples near the Sangonomiya Shrine was titrated against 0.01000 M EDTA to test its water…
A: First case: 50 ml water+ NaOH required 13.5 ml of 0.0100 M EDTA Second case: 50 ml water required…
Q: You are asked to titrate a Mn3+ solution with EDTA at pH 9.00. The overall ionic strength of the…
A: Solution- Log k = 25.2k =1025.2 nowαEDTA4−=5.4 ×10−2×1025.2 at pH=9(a) k'(conditional formation…
Q: A total of 5 mL of blood samples were treated with trichloroacetic acid to precipitate proteins.…
A: Solution: In this question we have to calculate the Pb concentration in ppm.
Q: A 25.00 mL suspension of milk of magnesia was added to 50.00 mL of 0.1400 M HNO3. The resulting…
A:
A 50.00-mL aliquot of solution containing 0.358 of MgSO4 (FM 120.37) in 0.500 L required 38.08 mL of EDTA solution for titration. How many milligrams of CaCO3 (FM 100.09) will react with 1.00 mL of this EDTA solution?
Step by step
Solved in 3 steps
- The accompanying data (1.00-cm cells) were obtained for the spectrophotometric titration 10.00 mL of Pd(II) with 2.44 10-4 M Nitroso R(O. W Rollins and M. M. Oldham, Anal. chem .,1971, 43, 262, DOI: 10.1021/ac60297a026). Calculate the concentration of the Pd(II) solution, given that the ligand-to-cation ratio in the colored product is 2:1A50.0 mL aliquot of solution contairing 0.450 g of MgSO4 [FM 120.27) in 0.500 L required 376 mL of EDTA solution for titration. How many miligrams of CaCO3 (FM 106.09) will react with 100 mL of this EDTA solution?A 30-mL portion of a solution containing Ca2+ and Mg2+ was titrated with 28.19 mL of 0.213 M EDTA at pH 10. Another 30-mL aliquot of the same Ca-Mg mixture was treated with NaOH to make the solution strongly alkaline and precipitate Mg(OH)2. This solution was then titrated with the same EDTA solution. What would be the required EDTA volume (in mL) to reach the endpoint of the second aliquot if it was found that there was 0.061 M of Mg2+ in the sample?
- a. A deepwell water sample of 100 mL was titrated with 0.010 M EDTA at pH 10 ( with Mg-EDTA pH 10 buffer reagent) and consumed 31 mL. Calculate the Total Hardness of the water sample as mg CaCO3. b. A deepwell water sample of 100 mL was titrated with 0.010 M EDTA at pH 12 and consumed 31 mL. Calculate the Calcium content of the water sample in mg/L.A 5.00 mL tap water sample was measured out with a volumetric pipette, and added to a 25 mL Erlenmeyer flask. It was then titrated with a 0.0100 M Na2EDTA.2H2O solution, and found to take 0.635 mL of the EDTA solution to reach the blue endpoint.A 5.00 mL sample that contains the borate ion {B4O5(OH)42-} at 35oCwas transferred to an Erlenmeyer flask and diluted with water to ~25 mL. This solution was titrated with 20.9 mL of 0.21 M HCl to the bromocresol green endpoint. What is the Ksp for the borax? Report your Ksp value to 3 decimal places.
- Calculate the PCa vs. EDTA titration curve for 50.0 mL of 0.0060 M Ca2+ being titrated with 0.0150 M EDTA in a solution buffered to a constant pH of 10.00. After the addition of 0.00 mL After the addition of 5.00 mL After the addition of 26.00 mLA deepwell water sample of 100 mL was titrated with 0.010 M EDTA at pH 12 and consumed 31 mL. Calculate the Calcium content of the water sample in mg/L.A 50.00 ml aliquot of a solution containing Ca2+ and Mg2+ was buffered at pH 10 and titrated with 0.0418 M EDTA. The endpoint volume was 44.36 ml. A second aliquot of the same mixture was made strongly basic by the addition of NaOH – this causes the Mg2+ to precipitate as Mg(OH)2. The solution was then titrated with the 0.0418 M EDTA and the endpoint volume was found to be 30.02 ml. Calculate the molar concentration of Mg.
- A solution containing 1.263 g of unknown potassium compound was dissolved in water and treated with excess sodium tetraphenylborate, Na1B1C6H524 solution to precipitate 1.003 g of insoluble K1B1C6H524 (FM 358.33). Find wt% K in the unknown.A 25.00 mL sample containing Fe3+ was treated with 10.00 mL of 0.03676 M EDTA to complex all the Fe3+ and leave excess EDTA in solution. The excess EDTA was then back-titrated, requiring 2.37 mL of 0.04615 M Mg2+. What was the concentration of Fe3+ in the original solution in ppm Fe3+?A sample of anhydrous NaHCO3 (FM = 84.007) is suspected to be contaminated with eitherNaOH (FM = 39.997) or Na2CO3 (FM = 105.989). To verify the suspicion, a 0.7483 g sample was dissolved to prepare a 50.00 mL solution, and a 10.00 mL aliquot was taken to prepare a 100 mL solution, where 25.00 mL was analyzed using double flask method. If the sample requires 0.45 mL of standard 0.0125 N HCl to reach the phenolphthalein endpoint and 35.95 mL to reach the bromcresol green endpoint, calculate the percentage composition (in %w/w) of all the basic components in the sample.