8.14 Effectiveness of online courses. The Sloan Survey of Online Learning, "Going the Distance: Online Education in the United States, 2011," reported that 68% of college presidents believe that their online education courses are as good as or superior to courses that utilize traditional face-to-face instruction. a. Give the null hypothesis for testing the claim made by the Sloan Survey. b. Give the rejection region for a two-tailed test using = .01. a = .01.
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- Rogers, Farlow, and colleagues (1998) conducted an experiment to investigate whether donepezil improved cognitive function in patients with mild to moderate Alzheimer’s disease (AD). A total of 1,775 patients were randomly assigned to treatment with either donepezil or a placebo (a look-alike pill with no pharmacological effect). Cognitive function, as measured by the Alzheimer’s Disease Assessment Scale (ADAS-cog), was significantly improved in patients taking donepezil compared with the placebo group at weeks 12, 18, and 24. [Source: Rogers, S. L., Farlow, M. R., Doody, R. S., et al. (1998). A 24-week, double-blind, placebo controlled trial of donepezil in patients with Alzheimer’s disease. Neurology, 50, 136–145.] In this experiment, the independent variable is , and the dependent variable is . The individuals who are in the control condition are typically referred to as the control group. Here, the control group consists of . is a construct that is being tested in this…The National Association of Home Builders provided data on the cost of the most popular home remodeling projects. Sample data on cost in thousands of dollars for two types if remodeling projects are as follows. Kitchen Master Bedroom 25.2 18.0 17.4 22.9 22.8 26.4 21.9 24.8 19.7 26.9 23.0 17.8 19.7 24.6 16.9 21.0 21.8 23.6 a. Compute the sample mean and sample standard deviation for each type of project. b. Develop a point estimate of the difference between the population mean…An article reported the results of a peer tutoring program to help children learn to read. In the experiment, Form 2 of the Gates-MacGintie Reading Test was administered to both an experimental group and a control group after 6 weeks of instruction, during which the experimental group received peer tutoring and the control group did not. For the experimental group n1 = 30 children, the mean score on the vocabulary portion of the test was x1 = 368.4, with sample standard deviation s1 = 39.3. The average score on the vocabulary portion of the test for the n2 = 30 subjects in the control group was x2 = 349.2 with sample standard deviation s2 = 56.8. Use a 1% level of significance to test the claim that the experimental group performed better than the control group. What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to three decimal places.)
- An article reported the results of a peer tutoring program to help children learn to read. In the experiment, Form 2 of the Gates-MacGintie Reading Test was administered to both an experimental group and a control group after 6 weeks of instruction, during which the experimental group received peer tutoring and the control group did not. For the experimental group n1 = 30 children, the mean score on the vocabulary portion of the test was x1 = 368.4, with sample standard deviation s1 = 39.3. The average score on the vocabulary portion of the test for the n2 = 30 subjects in the control group was x2 = 348.6 with sample standard deviation s2 = 56.2. Find a 98% confidence interval for ?1 − ?2. (Round your answers to two decimal places.) lower limit upper limitIn order to investigate a claim that the average time required for the county fire department to respond to a reported fire is greater than 15 minutes, county staff determined the response times for 40 randomly selected fire reports. The data was used to test H0H0: μ = 15 versus HaHa: μ > 15 and the computed P‐value was 0.12. If a 0.05 level of significance is used, what conclusions can be drawn? There is convincing evidence that the mean response time is 15 minutes (or less). There is convincing evidence that the mean response time is greater than 15 minutes. There is not convincing evidence that the mean response time is greater than 15 minutes.A researcher was interested in the relationship between a swimmer’s hand length and corresponding time to complete the 100-meter freestyle. The researcher selected a random sample of twenty swimmers from all participants in a swim competition. Assuming all conditions for inference are met, which of the following significance tests should be used to investigate whether there is convincing evidence, at a 5 percent level of significance, that a longer hand length is associated with a decrease in the time to complete the 100-meter freestyle?
- An online clothing retailer is testing a new e-mail campaign by sending one version of the e-mail with the word “free” in the subject line (version A) to a group of 1,500 customers and another version of the e-mail with word “discount” in the subject line (version B) to a different group of 1500 customers. After tracking the responses to the two versions of the e-mail advertising, the retailer finds that 75 responded to version A and 105 responded to version B. At 0.05 significance level, can it be concluded that the response rate for version B is higher than the response rate to version A What is your decision? Enter “R” if your decision is to reject the null hypotheses. Enter “F” if the decision is fail to/do not reject the null hypotheses. Your answer (R/F) is: Which of the followings is the most appropriate conclusion for the hypotheses test? Enter the number corresponding to the most appropriate conclusion in the answer box. For example, if statement number 2 is the most…An online clothing retailer is testing a new e-mail campaign by sending one version of the e-mail with the word “free” in the subject line (version A) to a group of 1,500 customers and another version of the e-mail with word “discount” in the subject line (version B) to a different group of 1500 customers. After tracking the responses to the two versions of the e-mail advertising, the retailer finds that 75 responded to version A and 105 responded to version B. At 0.05 significance level, can it be concluded that the response rate for version B is higher than the response rate to version A Determine which of the following formulations of the hypotheses is appropriate and enter the corresponding number in the answer text box. Index “a” refers to the population of the customers who respond to version A and index “b” refers to the population of customers who are responsive to version B. Identify and enter the number corresponding to the most appropriate formulation for the…The Youth Risk Behavior Survey (a study of public high school students) showed that 45 of 675 girls and 103 of 621 boys had been in a physical fight on school property one or more times during the past 12 months Using 5% significance, perform an appropriate test of hypothesis that the proportion of girlsinvolved in a physical fight on school property is less than the proportion of boys involved in a physical fight on school property.Step 1: H0: ________________ Ha: ____________________ Significance level α =0.05Step 2: Check necessary data conditions and compute an appropriate test statistic:Step 3: Compute corresponding p-value
- On snow-covered roads, winter tires enable a car to stop in a shorter distance than if summer tires were installed. In terms of the additive model for one-way ANOVA, and for an experiment in which the mean stopping distances on a snow-covered road are measured for each of four brands of winter tires. If the data are as shown in Sheet 48, what conclusion would be reached at the 0.01 level of significance? Shett 48 Supplier A 517 484 463 452 502 447 481 500 485 566 Supplier B 479 499 488 430 482 457 424 488 526 455 Supplier C 435 443 480 465 435 430 465 514 463 510 Supplier D 526 537 443 505 468 533 481 477 490 470 Select one: a) p-value = 0.28 greater than 0.05, the average distance is different for at list two tires b) F stat = 1.86, F crit = 4.38, not enough evidence to claim that the average distance is different for at list two tires c) F ratio = 4.38, not enough evidence to claim that the average distance is different for at list two tires d) F stat = 0.68, F…In a study of the effectiveness of a fabric device that acts like a support stocking for a weak or damaged heart, 110 people who consented to treatment were assigned at random to either a standard treatment consisting of drugs or the experimental treatment that consisted of drugs plus surgery to install the stocking. After two years, 30% of the 60 patients receiving the stocking had improved and 24% of the patients receiving the standard treatment had improved. (Use a statistical computer package to calculate the P-value. Use pexperimental − pstandard. Round your test statistic to two decimal places and your P-value to four decimal places.) z = ? P = ?According to the U.S. Transportation Security Administration (TSA), 2% of the 771,556,886 travelers who utilized 440 federalized airports in 2017 waited more than 20 minutes in the TSA security line. The File TSAWaitTimes contains waiting Times in TSA security lines at a major U.S. airport for a recent random sample 10,531 travelers. Use these Data to test the hypothesis that the proportion of travelers waiting more than 20 minutes in TSA security lines at this airport is the same as the national proportion at α = .05 Data given: Time In Line Mean 11.99496 Median 11.97536 Standard Deviation 3.992043 Confidence Level(95.0%) 0.076253 Provide a 95% confidence interval with interpretation