Answered: 80 mm 20 mm 10 mm 10 mm м м 10 mm

Engineering

Mechanical Engineering

80 mm 20 mm 10 mm 10 mm м м 10 mm

Precision Machining Technology (MindTap Course List)

2nd Edition

ISBN:9781285444543

Author:Peter J. Hoffman, Eric S. Hopewell, Brian Janes

Publisher:Peter J. Hoffman, Eric S. Hopewell, Brian Janes

Chapter3: Job Planning, Benchwork, And Layout

Section3.1: Understanding Drawings

Problem 1RQ: Information such as tolerances and scale can be found in the________ of an engineering drawing.

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Concept explainers

Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.

Question

The bar is subjected to a moment of M = 100 N # m. Determine the maximum bending stress in the bar and sketch, approximately, how the stress varies over the critical section.

Expert Solution

Step 1

Given

Moment = 100 Nm

D = 80 mm = 0.08 m

d = 20 mm = 0.02 m

t = 10 mm = 0.01 m

r = 10 mm = 0.01 m

To find

Maximum bending stress

Diagrammatically representation of stress in critical area

Step 2

Stress concentration

$\frac{D}{d} = \frac{0.08}{0.02} = 4 \frac{r}{d} = \frac{0.01}{0.02} = 0.5 k = 1.26$

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