How to slove this question For Problems 4 9, calculate the flux of the vector field through the given surface.4. F = zk through a square of side length 5 in the plane z = 2. The square is centered on the z-axis, has sidesparallel to the axes, and is oriented in the positive z-direction.5. F(x2 – 2) i through a square of side length 3 in the yz-plane, oriented in the negative r-direction.6. F = z(x2 + y²) k through the disk of radius 4 in the plane z = 2, centered on the z-axis, oriented upward.7. F = (e-x²-y')k through the disk of radius 2 in the ry-plane, oriented upward.8. F = 7+2xi+ 4y k, and S is the part of the surface z = 2x2 + y + 3 above the square 0 < x < 1, 0 < y < 1,oriented upward.9. F = xỉ+ (x + 2y – 8)3+ 2z k, and S is the part of the surface z = 4 – x? – yin the first octant (see figure to the right), oriented upward.

Flux flux is something that is constantly changing and passes through any cross-sectional area.

Answered: 9. F = xỉ+ (x + 2y – 8)j+ 2z k, and S…

9. F = xỉ+ (x + 2y – 8)j+ 2z k, and S is the part of the surface z = 4 – x2 . in the first octant (see figure to the right), oriented upward.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.10OQ: A cubical gaussian surface is bisected by a large sheet of charge, parallel to its top and bottom...

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How to slove this question

For Problems 4 9, calculate the flux of the vector field through the given surface.
4. F = zk through a square of side length 5 in the plane z = 2. The square is centered on the z-axis, has sides
parallel to the axes, and is oriented in the positive z-direction.
5. F
(x2 – 2) i through a square of side length 3 in the yz-plane, oriented in the negative r-direction.
6. F = z(x2 + y²) k through the disk of radius 4 in the plane z = 2, centered on the z-axis, oriented upward.
7. F = (e-x²
-y')k through the disk of radius 2 in the ry-plane, oriented upward.
8. F = 7+2xi+ 4y k, and S is the part of the surface z = 2x2 + y + 3 above the square 0 < x < 1, 0 < y < 1,
oriented upward.
9. F = xỉ+ (x + 2y – 8)3+ 2z k, and S is the part of the surface z = 4 – x? – y
in the first octant (see figure to the right), oriented upward.

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