A 0.16 pF parallel-plate capacitor is charged (using a battery) to 10 V. Now the battery is disconnected from the capacitor and 10^7 electrons are placed on the negative plate. The new voltage between the plates of the capacitor: is increased by 10 V is decreased by 10 V is decreased by 20 v is increased by 5 V In xy-plane, points A(2 m ; 3 m) and B(5 m; 7 m) are in a region where the electric field is uniform and is given by E = (4i - 3j) N/C. What is the potential difference AV = VA - VB? %3D %3D O av = 24 V O av = 6 V O av = 0 V O AV = 12 V

Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter7: Tunneling Phenomena
Section: Chapter Questions
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A 0.16 pF parallel-plate capacitor is charged
(using a battery) to 10 V. Now the battery is
disconnected from the capacitor and 10^7
electrons are placed on the negative plate.
The new voltage between the plates of the
capacitor:
is increased by 10 V
is decreased by 10 V
is decreased by 20 v
is increased by 5 V
In xy-plane, points A(2 m; 3 m) and B(5 m; 7
m) are in a region where the electric field is
uniform and is given by E = (4i - 3j) N/C. What
is the potential difference AV = VA - VB?
%3D
O aV = 24 V
AV = 6 V
O av = 0 V
AV = 12 V
Transcribed Image Text:A 0.16 pF parallel-plate capacitor is charged (using a battery) to 10 V. Now the battery is disconnected from the capacitor and 10^7 electrons are placed on the negative plate. The new voltage between the plates of the capacitor: is increased by 10 V is decreased by 10 V is decreased by 20 v is increased by 5 V In xy-plane, points A(2 m; 3 m) and B(5 m; 7 m) are in a region where the electric field is uniform and is given by E = (4i - 3j) N/C. What is the potential difference AV = VA - VB? %3D O aV = 24 V AV = 6 V O av = 0 V AV = 12 V
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