A 0.207-kg particle undergoes simple harmonic motion along the horizontal x-axis between the points x1 = -0.349 m and x2 = 0.487 m. The period of oscillation is 0.643 s. Find the frequency, f, the equilibrium position, xeq, the amplitude, A, the maximum speed, vmax, the maximum magnitude of acceleration, amax, the force constant, k, and the total mechanical energy, Eot - f = Hz Xeq A = Umax m/s Amax = m/s? k = N/m E1ot J

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Chapter12: Oscillatory Motion
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Problem 14P: In an engine, a piston oscillates with simple harmonic motion so that its position varies according...
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A 0.207-kg particle undergoes simple harmonic motion along the horizontal x-axis between the points x = -0.349 m and
x2 = 0.487 m. The period of oscillation is 0.643 s. Find the frequency, f, the equilibrium position, xeq, the amplitude, A, the
maximum speed, vmax, the maximum magnitude of acceleration, amax, the force constant, k, and the total mechanical
energy, Etot-
f =
Hz
Xeq
A =
Umax =
m/s
Amax =
m/s?
k =
N/m
Etot =
J
Transcribed Image Text:A 0.207-kg particle undergoes simple harmonic motion along the horizontal x-axis between the points x = -0.349 m and x2 = 0.487 m. The period of oscillation is 0.643 s. Find the frequency, f, the equilibrium position, xeq, the amplitude, A, the maximum speed, vmax, the maximum magnitude of acceleration, amax, the force constant, k, and the total mechanical energy, Etot- f = Hz Xeq A = Umax = m/s Amax = m/s? k = N/m Etot = J
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