A 0.338 g sample of an unknown triprotic acid dissolved in water is titrated to the second equivalence point using 22.2 mL of 0.163 M NaOH. Calculate the molar mass of this acid. The correct answer is 187g/mol. a) Explain in detail how to arrive at the answer of 187 g/mol and why certain equations are used. b) Explain why is the answer 187 g/mol and not 280 g/mol?

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Chapter16: Acid-base Equilibria
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Problem 16.117QP: A 0.288-g sample of an unknown monoprotic organic acid is dissolved in water and titrated with a...
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A 0.338 g sample of an unknown triprotic acid dissolved in water is titrated to the second equivalence point using 22.2 mL of 0.163 M NaOH. Calculate the molar mass of this acid.

The correct answer is 187g/mol.

a) Explain in detail how to arrive at the answer of 187 g/mol and why certain equations are used.

b) Explain why is the answer 187 g/mol and not 280 g/mol?

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