A 1.00-kg glider attached to a spring with a force constant 25.0 N/m oscillates on a frictionless, horizontal air track. At t= 0, the glider is released from rest at x = -3.20 cm (that is, the spring compressed by 3.20 cm). (a) Find the period of the glider's motion. 1.26 S (b) Find the maximum values of its speed and acceleration. speed 0.16 ✔ m/s acceleration 0.80 ✓ m/s² (c) Find the position, velocity, and acceleration as functions of time. (Where position is in m, velocity is in m/s, acceleration is in m/s², and t is in s. Use the following as necessary: t.) x(t) = -3.20 v(t) = a(t)= 0.80 Need Help? Submit Answer Read It X X X Watch It

Principles of Physics: A Calculus-Based Text
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Chapter12: Oscillatory Motion
Section: Chapter Questions
Problem 10P: A 1.00-kg glider attached to a spring with a force constant of 25.0 N/m oscillates on a...
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Please help me solve ALL of part C. I am confused how to solve for it. 

A 1.00-kg glider attached to a spring with a force constant 25.0 N/m oscillates on a frictionless, horizontal air track. At t = 0, the glider is released from rest at x = -3.20 cm (that is, the spring is
compressed by 3.20 cm).
(a) Find the period of the glider's motion.
1.26
S
(b) Find the maximum values of its speed and acceleration.
speed
0.16
m/s
m/s²
acceleration 0.80
(c) Find the position, velocity, and acceleration as functions of time. (Where position is in m, velocity is in m/s, acceleration is in m/s², and t is in s. Use the following as necessary: t.)
x(t) = -3.20
v(t) =
a(t) = 0.80
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Submit Answer
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Transcribed Image Text:A 1.00-kg glider attached to a spring with a force constant 25.0 N/m oscillates on a frictionless, horizontal air track. At t = 0, the glider is released from rest at x = -3.20 cm (that is, the spring is compressed by 3.20 cm). (a) Find the period of the glider's motion. 1.26 S (b) Find the maximum values of its speed and acceleration. speed 0.16 m/s m/s² acceleration 0.80 (c) Find the position, velocity, and acceleration as functions of time. (Where position is in m, velocity is in m/s, acceleration is in m/s², and t is in s. Use the following as necessary: t.) x(t) = -3.20 v(t) = a(t) = 0.80 Need Help? Submit Answer Read It Watch It
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