A 100-N block on a rough 30°-incline is acted upon by a force P as shovm causing it to accelernte atKinetic friction is 0.30. (a) Draw the FBD of the block (b) Find the magnitude of P.Please explain in full detail Griveya= 2 m/s²W = 100Nk = 0.30P = ?P20⁰^Nwsin30&w30°Free body diagrama금W51430f=l₂NNwcostoPcos 50°M(wcas30° + psin50") EFy =oN = Wc0830° + P.5in50E FxmaPcos 50° - ( + wsin 30°)= ma =aPc 08 50° - lk (w80830° + Psi450°) - wsin 30° =P (C0850° + Mk sin50°) =WP(co8 50° - 4k Sin 50°)=w (9W(ag+ sin36° +kk (0830⁰)...P=Cos 50⁰ ·lk sin50"100x (2/9-8 + 0.5 +003x√3/2)(c0850° 0-3801150°)233-40 N==P= 233-40 Naux(ујаa + wsin 30° + Mk WcOs 30²+ sin 30° + k Co836°• Mk (0836°)

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University Physics Volume 3

17th Edition

ISBN:9781938168185

Author:William Moebs, Jeff Sanny

Publisher:William Moebs, Jeff Sanny

Chapter5: Relativity

Section: Chapter Questions

Problem 14CQ: How does modern relativity modify the law of conservation of momentum?

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A 100-N block on a rough 30°-incline is acted upon by a force P as shovm causing it to accelernte at Kinetic friction is 0.30. (a) Draw the FBD of the block (b) Find the magnitude of P. Please explain in full detail

Grivey
a= 2 m/s²
W = 100N
k = 0.30
P = ?
P
20⁰
^N
wsin30
&w
30°
Free body diagram
a
금
W51430
f=l₂N
N
wcosto
Pcos 50°
M
(wcas30° + psin50")

EFy =o
N = Wc0830° + P.5in50
E Fx
ma
Pcos 50° - ( + wsin 30°)
= ma =
a
Pc 08 50° - lk (w80830° + Psi450°) - wsin 30° =
P (C0850° + Mk sin50°) =
W
P(co8 50° - 4k Sin 50°)
=
w (9
W
(ag
+ sin36° +kk (0830⁰)
...
P=
Cos 50⁰ ·lk sin50"
100x (2/9-8 + 0.5 +003x√3/2)
(c0850° 0-3801150°)
233-40 N
=
=
P= 233-40 N
aux
(уја
a + wsin 30° + Mk WcOs 30²
+ sin 30° + k Co836°
• Mk (0836°)

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