A 120.0 mL sample of 0.040 M Ca²+ is titrated with 0.040 M EDTA at pH 9.00. The value of log Kf for the Ca²+-EDTA complex is 10.65 and the fraction of free EDTA in the Y“- form, ays-, is 0.041 at pH 9.00. What is K', the conditional formation constant, for Ca²+ at pH 9.00? K{ = 1.83 x10° What is the equivalence point volume, Ve, in milliliters? Ve = 132 mL Incorrect Calculate the concentration of Ca²+ at V = }Ve. [Ca²+] = 5.6 x10-9 M Incorrect Calculate the concentration of Ca²+ at V = V.. [Ca2+] = | 0.0133 M Incorrect Calculate the concentration of Ca²+ at V = 1.1V. [Ca2+] = | 0.0200 M Incorrect

Appl Of Ms Excel In Analytical Chemistry
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ISBN:9781285686691
Author:Crouch
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Chapter10: Potentiometry And Redox Titrations
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A 120.0 mL sample of 0.040 M Ca²+ is titrated with 0.040 M EDTA at pH 9.00. The value of log Kf for the Ca²+–EDTA
complex is 10.65 and the fraction of free EDTA in the Y form, ays-, is 0.041 at pH 9.00.
What is K, the conditional formation constant, for Ca²+ at pH 9.00?
K = 1.83 x10°
What is the equivalence point volume, Ve, in milliliters?
Ve = 132
mL
Incorrect
Calculate the concentration of Ca2+ at V =
[Ca2+] = | 5.6 x10-9
M
Incorrect
Calculate the concentration of Ca2+ at V = Ve.
[Ca?+] = 0.0133
M
Incorrect
Calculate the concentration of Ca²+ at V = 1.1Ve.
[Ca?+] = 0.0200
M
Incorrect
Transcribed Image Text:A 120.0 mL sample of 0.040 M Ca²+ is titrated with 0.040 M EDTA at pH 9.00. The value of log Kf for the Ca²+–EDTA complex is 10.65 and the fraction of free EDTA in the Y form, ays-, is 0.041 at pH 9.00. What is K, the conditional formation constant, for Ca²+ at pH 9.00? K = 1.83 x10° What is the equivalence point volume, Ve, in milliliters? Ve = 132 mL Incorrect Calculate the concentration of Ca2+ at V = [Ca2+] = | 5.6 x10-9 M Incorrect Calculate the concentration of Ca2+ at V = Ve. [Ca?+] = 0.0133 M Incorrect Calculate the concentration of Ca²+ at V = 1.1Ve. [Ca?+] = 0.0200 M Incorrect
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