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A 2.40-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 70 kg construction worker stands at the far end of the beam. What is the magnitude of the torque about the bolt due to the worker and the weight of the beam?

Question

A 2.40-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 70 kg construction worker stands at the far end of the beam. What is the magnitude of the torque about the bolt due to the worker and the weight of the beam?

 
check_circleAnswer
Step 1

Given values:

Length of steel beam, L = 2.40 m

Mass of steel beam, M = 500 kg

Mass of worker, m = 70 kg

Step 2

We know:

Torque = force x perpendicular distance

Net torque = ...

= t
net
steel
worker
L
+Fworker X L
2
=F.
steel
L
Mgx mgxL
2
Plugging in the given values:
2.4
70 x 9.8x2.4
2
500x 9.8x -
5880 1646.4
=7526.4 N.m
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= t net steel worker L +Fworker X L 2 =F. steel L Mgx mgxL 2 Plugging in the given values: 2.4 70 x 9.8x2.4 2 500x 9.8x - 5880 1646.4 =7526.4 N.m

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