A 280 g mass vibrates according to the equationTime left 1:59:14x = 0.45sin(6.5t), where x is in meters and t is in seconds.[Recommended time : 4-5 minutes](a) the amplitude (m)Oa. 0.225Ob. 0.45Oc. -0.45Od. 6.5Oe. -6.5(b) the frequency (/s)Oa. 1.03Ob. 0.967Oc. 40.8Od. 6.5(c) the period (s) Time left 1:59:30Quiz navigationYou are driving a car at 140 km/h, and suddenly you see a motorbike at 530 mahead. The bike is moving away at a constant speed of 45 km/h. You push on thebreaks as hard as you can! [Recommended time : 10-12 minutes](a) What shuold be the final velocity of your car to just avoid collission at the lastmoment? (km/h)Qusai Al AdawiOa. 0126979Ob. 4534.Oc. 9510 1112Od. 50Finish attempt.(b) What must be the deceleration of your car to avoid hitting the bike? (km h-2)Oa. -18490.6Ob. -1910.4Oc. -8514.2Od. -7641.5

Name: A 280 g mass vibrates according to the equationTime left 1:59:14x = 0
Uploaded: 2024-03-20T06:58:04.000Z
Channel: Bartleby
Description: A 280 g mass vibrates according to the equationTime left 1:59:14x = 0.45sin(6.5t), where x is in meters and t is in seconds.[Recommended time : 4-5 minutes](a) the amplitude (m)Oa. 0.225Ob. 0.45Oc. -0.45Od. 6.5Oe. -6.5(b) the frequency (/s)Oa. 1.03O

“Since you have asked multiple question, we will solve the first question for you. If you want any…

Science

Physics

A 280 g mass vibrates according to the equation x = 0.45sin(6.5t), where x is in meters and t is in seconds. [Recommended time : 4-5 minutes] (a) the amplitude (m) Oa. 0.225 Ob. 0.45 Oc. -0.45 Od. 6.5 Oe. -6.5

A 280 g mass vibrates according to the equation x = 0.45sin(6.5t), where x is in meters and t is in seconds. [Recommended time : 4-5 minutes] (a) the amplitude (m) Oa. 0.225 Ob. 0.45 Oc. -0.45 Od. 6.5 Oe. -6.5

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter3: Two-dimensional Kinematics

Section: Chapter Questions

Problem 59PE: (a) In what direction would the ship in Exercise 3.57 have to travel in order to have a velocity...

See similar textbooks

Similar questions

2. Wellington Wildcat is rushing to get to a parade in time to be the grand marshal. He’s standing in theback of a flatbed truck while McFogg the Dog races at 25 m/s towards town. Suddenly, McFogg sees atiny maple leaf in the road 55 m ahead, and, being a proud Canadian, slams on the brakes to protect thesacred totem. Since McFogg is known to ride the brakes like a real jerk, let’s assume his reaction time tohit the breaks is essentially zero.A. Can McFogg actually stop before the truck reaches the leaf? The coefficients of friction betweenrubber tires and dry concrete are: μs = 1.00, μk = 0.80. When answering this question, be sure toinclude a free-body diagram representing the truck and its stellar mascots as a single object.B. Now here’s the real serious question: Is it possible for McFogg to stop short of the leaf such thatWellington does not slip and slide into the back of the truck cab? The coefficients of friction forWellington’s shoes on the bed of the truck are: μs = 0.60, μk…
I'm not sure how to solve this! I tried and got 1.3 / 2.4 seconds. Am i right? Could you explain how to do it if i'm not? Cheers ! In a classic Seinfeld episode, Jerry tosses a loaf of bread (a marble rye) straight upward to his friend George who is leaning out of a third-story window. If the loaf of bread leaves Jerry's hand at a height of 1 m with an initial velocity of 18 m/sec, write an equation for the vertical position of the bread s (in meters) t seconds after release. How long will it take the bread to reach George if he catches the bread on the way up at a height of 16 m? Round to the nearest tenth of a second.
Plus and minus signs are used in one-dimensional motion to indicate direction. What is the sign of an acceleration that reduces the magnitude of a negative velocity? Of a positive velocity?
Give an example in which velocity is zero yet acceleration is not.
If the car in the preceding example continues to accelerate at the same rate for an additional 3.0 s, what will be the magnitude of its velocity in m/s at the end of this time?
(a) In what direction would the ship in Exercise 3.57 have to travel in order to have a velocity straight north relative to the Earth, assuming its speed relative to the water remains 7.00 m/s? (b) What would its speed be relative to the Earth?
A Wide Reciever is running along the sideline straight towards the goal at a constant speed. When he is 27 m away from the goal line he cathces the ball, but theire is a cornerback 12 m behind him moving with a connstant speed of vc=9.0 m/s what speed should the wide reveiver have to make sure he reaches the goal line just as the cornerback reaches him.
Please answer this NEATLY, COMPLETELY, and CORRECTLY for an UPVOTE. The position ? of a particle along a straight line is given by s = sin(0.4t) - 10t + 20t2 , where s is in meters and t is the time in seconds. Determine the position s and the velocity v when the acceleration of the particle is 38.84 m/s2.
you’re windsurfing at 6.28 m/s when a gust hits, accelerating your sailboardat 0.714 m/s2at 48.8◦to your original direction. If the gust lasts 5.42 s, what’s themagnitude of the board’s displacement during this time?
IV. A stone dropped from a cliff hits the ground 3.00 slater. Assuming the acceleration due to gravity is 9.81m/s2 , finda. the velocity of the stone the instant before it hitsthe groundb. the displacement experienced by the stone init’s fall
When last we left our friend Wile E. Coyote (SuperGenius), was peeling himself off a canyon wall and none the worse for wear. This time, he has obtained an Acme^ TM rocket-powered dragster with the AcmeTM Premium Parachute Braking System (patent pending)Starting from restthe dragster accelerates at a constant rate of 36.4 m/s ^ 2 for 14 seconds. At this point, the coyote realizes that he has passed the Road Runner and so he instantly cuts off the engine and deploys his braking system - which doesn't work. He therefore travels an additional distance of 1800 m at constant velocity until again becoming one with a canyon wall. Determine: (a) The total time for Wile E. Coyote's motion described above; on (b) The total distance covered by Wile E. Coyote's motion described above ; (c) The average velocity for Wile E. Coyote's motion described above.
Win Blonehare and Kent Swimtashore are sailboating in Lake Gustastorm. Starting from rest near the shore, they accelerate with a uniform acceleration of 1.59 m/s2, How far (in m) are they from the shore after 12.3 seconds?