A 35.0 mL volume of ammonia (NH3) household cleaner needs 53.75 mL of 0.300 M HNO3 to completely neutralize the base. The balanced equation is: HNO3 + NH3 --> NH4NO3 A) Find the number of moles of HNO3 involved in this reaction. (2 hints: start dimensional analysis with the volume of HNO3, & convert mL to L.) B) Find the molarity (M) of the NH3 (This is different than the number of moles. Your calculation will be different from part A.) C) Find the mass/mass % of the NH3. You will need the molar mass of NH3 (17.04 g/mol) & the density of NH3 (0.985 g/mL).

A 35.0 mL volume of ammonia (NH3) household cleaner needs 53.75 mL of 0.300 M HNO3 to completely neutralize the base. The balanced equation is: HNO3 + NH3 --> NH4NO3 A) Find the number of moles of HNO3 involved in this reaction. (2 hints: start dimensional analysis with the volume of HNO3, & convert mL to L.) B) Find the molarity (M) of the NH3 (This is different than the number of moles. Your calculation will be different from part A.) C) Find the mass/mass % of the NH3. You will need the molar mass of NH3 (17.04 g/mol) & the density of NH3 (0.985 g/mL).

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter3: Statistical Tests With Excel

Section: Chapter Questions

Problem 5P

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