A 35.6 mL solution of 15.8 M HCl is diluted to 191 mL.  What is the new concentration of the acid solution (in M)?

Q: In the laboratory you dilute 4.23 mL of a concentrated 12.0 M hydroiodic acid solution to a total…

A: Given  Initial Volume ( V1 )             = 4.23 mL  Initial Concentration ( M1 ) = 12 M  Final…

Q: You wish to make a 0.354 M hydroiodic acid solution from a stock solution of 12.0 M hydroiodic acid.…

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Q: How many milliliters of 12.0 M HCI(aq) are needed to prepare 595.0 mL of 1.00 M HCI(aq)?

A: Given: The initial concentration of HCl, (M1) = 12 M. The final concentration of HCl, (M2) = 1.0 M.…

Q: Commercial hydrochloric acid is 12.1 M. What volume of commercial HCI solution should be used to…

A: Given, initial molarity of HCl = 12.1M.            Final molarity of HCl = 3.00M            Final…

Q: you have a 1.250 M HCl solution and you need to make 500.0 mL's of 0.1000 M HCl solution. What…

A: Consider the given information is as follows; The initial concentration of HCl M1 = 1.250 M The…

Q: What is the concentration of a solution made by diluting 35 mL of 6.0 M HCI to a final volume of 750…

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Q: What is the concentration of HCl if 65 mL of a 9.0 M HCl solution is diluted with pure water to a…

A: The molarity of a given solution is the number of moles (dissolved) of solute in one liter of the…

Q: What is the concentration of a solution made by diluting 45 mL of 6.0 M HCl to a final volume of 750…

A: M1V1 = M2V2

Q: 1.50 mol of NaOH in 1000. mL total volume of solution

A: Given that , the mol of sodium hydroxide, NaOH Solution = 1.50 mol And , volume of the solution =…

Q: 15 ml sample of 0.45 M K,Cro, is diluted to 100 ml. What is the concentration of the new solution?

A: On dilution of a solution, number of moles of the solution remains constant. So, the product of…

Q: What volume (in ml)  of a 12.00M stock solution of HCl is required to prepare 500.00ml of a 3.65…

A: The mass of HCl standard = Density × Volume The mass of HCl standard = 3.65 × 10-3 g/mL × 500 mL =…

Q: If 12.00 mL of solvent is added to 8.00 mL of a 0.625 M solution, what is the concentration (in M)…

A: Since the concentration of solution is given by  concentration = moles of solute / volume of…

Q: If you wished to prepare 1.50 liter of 0.30 M HCl solution from a stock solution that has a…

A: Applying molarity equation M1V1= M2V2

Q: It is desired to prepare 0.500 L of a 0.125 M solution of NaCI from a 1.00 M stock solution. How…

A: molarity is defined as no of moles of solute devided by volume of solution in liter

Q: A 230. -mL sample of a ‍0.275 M cacl2 solution is left on a hot plate overnight; the following…

A: Molarity equation  The equation that relates two solution with same number of moles of solute is…

Q: What is the concentration of nitric acid in the final solution?

A:

Q: What is the concentration of a solution made by diluting 85 mL of 6.0 M HCl to a final volume of 750…

A: Given is  Molarity before dilution (M1)= 6 Volume before dilution (V1)=85ml  Volume after dilution…

Q: What volume of a 0.351 M perchloric acid solution is required to neutralize 20.3 mL of a 0.171 M…

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Q: What initial volume, in milliliters, of a 2.40 M NaCl solution is needed to prepare 80.0 mL of a…

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Q: What is molar concentration of a 350 mL solution that contains 10.5 g of NaOH? Determine the volume…

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Q: A laboratory custodian needed to prepare 4590 mL of a 2.45 N solution of HCl for the conduct of…

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Q: When 296 mL of water are added to 19.2 mL of 19 M HCl, what will be the new molarity?

A: Molarity = No. ofmoles of soluteVolume of solution(in L)

Q: How many milliliters of 10.0 M HCl(aq) are needed to prepare 920.0 mL of 1.00 M HCl(aq)?

A: • The values provided in the question are:-       i) Initial concentration of HCl solution, M1 =…

Q: What volume of a 0.115 M hydrochloric acid solution is required to neutralize 11.0 mL of a 0.153 M…

A: The reaction between hydrochloric acid and barium hydroxide is given by  2 HCl + Ba(OH)2 ----->…

Q: What volume of a 0.143 M barium hydroxide solution is required to neutralize 23.3 mL of a 0.134 M…

A: The expression of dilution law is shown below: M1V1 =M2V2 where; M1 = molarity of known solution V1…

Q: A student prepared a standard copper solution by combining 4.12 mL of stock 0.3926 mol/L copper(II)…

A: Since the moles of copper(II) sulfate is coming from the copper(II) sulfate stock solution only…

Q: A Chemistry teacher needs to make 0.45 L of 0.2 M NaOH solution for a class experiment. What volume…

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Q: 10 mL of a 10.0 M stock solution of NaOH is diluted to 250 mL, what is the concentration of…

A: In the dilution process, the relationship between initial and final concentrations and volumes of…

Q: You wish to make a 0.315 M perchloric acid solution from a stock solution of 12.0 M perchloric acid.…

A: Given, the concentration of stock solution =12.0 Mconcentration of diluted solution =0.315 Mvolume…

Q: According to the label on a bottle of concentrated hydrochloric acid, the contents are 36.0% HCl by…

A: Given,Density of solution = 1.18 g/mLAnd the contents are 36.0% HCl by mass.Therefore, it means that…

Q: How many milliliters of 12.0 M HCl(aq) are needed to prepare 315.0 mL of 1.00 M HCl(aq)?

A: Given, M1 = 1.00M HCl            M2 = 12.0M HCl            V1 = 315.0mL            V2 = ?

Q: If 12.5 mL of a 0.20 M NaOH solution is diluted to 52.0mL, what is the concentration of the…

A: For dilution M.V = constant

Q: A stock solution of lithium sulfate has a concentration of 5.5 M. If 88.3 mL of stock solution is…

A: Given :-  Initial concentration (M1) = 5.5 M  initial volume (V1) = 88.3 mL  Final volume (V2) =…

Q: What volume of 3.63 M HClag) is needed to make 350.0 mL of a 0.169 M hydrochloric acid solution?

A: • The values provided in the question are:-    i) Initial concentration of HCl solution, M1 = 3.63 M…

Q: If you had to prepare a 0.200 M HCl solution from 21.0 mL of a 2.60 M HCl stock solution, to what…

A: Here given, Initial volume (V1) = 21 mL Initial strength (S1) = 2.6 M Final volume (V2) =? Final…

Q: A standard solution of HCI is 1.000 M. What mass of HCL is present in 157.0 ml of this solution?

A: Using Formula of molarity we can solve this problem.

Q: Concentrated hydrochloric acid is about 12.1 M. What volume of concentrated HCl is required to…

A: Given,  Molarity of HCl before dilution = M1 = 12.1 M  Final volume = V2 = 5500 mL  Molarity of HCl…

Q: calculate the concentration of solution prepared by adding 1.025 g of sodium chloride to enough…

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Q: What volume of a 0.173 M potassium hydroxide solution is required to neutralize 12.3 mL of a 0.369 M…

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Q: what volume of 12 M hydrochloric acid solution (HCI) is needed to prepare 750 mL of 3 M HCI…

A: The dilution is the process of mixing a solution having definite molarity with more volume of water…

Q: If you had a 3.50 M stock solution of NaOH, how many ml of this stock would be needed to prepare 565…

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Q: How many milliliters of 12.0 M HCl(aq) are needed to prepare 220.0 mL of 1.00 M HCl(aq)?

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Q: Upon adding 275 mL of water to 275 mL of a 0.310 M aqueous solution of NaOH, the concentration of…

A: HALF Concentration = Mass/Volume As the mass of NaOH, or moles of NaOH in solution does not changes…

Q: You are asked to prepare 850 mL of a 0.15 M HNO3 solution using a 2.5 M stock solution of HNO3. What…

A: To calculate the volume of stock solution and Volume of water needed , we would use dilution law of…

Q: What volume of 6.00 M HNO3 soulution is needed to prepare 1500 mL of 0.180 M HNO3 solution?

A: According to volumetric principle

Q: A 1.05 M of 225 mL solution is diluted to a new volume of 341 mL. What is the new concentration?

A: Given, Initial Molarity = 1.05 M  Initial volume = 225 mL  Final volume = 341 mL Final Molarity = ?

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.