A 36.0 mL sample of aqueous sulfuric acid was titrated with 0.250 M ROH(aq) until the acid-base indicator signaled that the solution was neutralized. The mixture was then carefully evaporated to dryness, the residue was dried in a drying oven. The residue was then weighed and a value of 861 mg was obtained for its mass. Calculate a value for the volume of the potassium hydroxide solution that was used in the titration from this data. O 12.7 mL O 19.8 mL O48.5 mL 39.5 mL

Chemistry: Principles and Reactions
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Chapter10: Solutions
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Problem 65QAP: Twenty-five milliliters of a solution (d=1.107g/mL)containing 15.25% by mass of sulfuric acid is...
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A 36.0 mL sample of aqueous sulfuric acid was titrated with 0.250 M ROH(aq) until
the acid-base indicator signaled that the solution was neutralized. The mixture was
then carefully evaporated to dryness, the residue was dried in a drying oven. The
residue was then weighed and a value of 861 mg was obtained for its mass.
Calculate a value for the volume of the potassium hydroxide solution that was used
in the titration from this data.
O 12.7 mL
O 19.8 mL
O48.5 mL
39.5 mL
Transcribed Image Text:A 36.0 mL sample of aqueous sulfuric acid was titrated with 0.250 M ROH(aq) until the acid-base indicator signaled that the solution was neutralized. The mixture was then carefully evaporated to dryness, the residue was dried in a drying oven. The residue was then weighed and a value of 861 mg was obtained for its mass. Calculate a value for the volume of the potassium hydroxide solution that was used in the titration from this data. O 12.7 mL O 19.8 mL O48.5 mL 39.5 mL
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