Question
Asked Oct 7, 2019
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A 55.0 mL sample of 0.102M potassium sulfate solution is mixed with 35.0 mL of a 0.114M lead(II) acetate solution and the precipitation reaction shown here occurs:

K2SO4(aq)+Pb(C2H3O2)2(aq)=2KC2H3O2(aq)+PbSO4(s).

Determine the limiting reagent.

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The given balanced equation is given along wit...

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Ph(CH022 K2SO4 2KC H O +PbSO, 2 3 4 Volume: 55. OmL 35.0mL Molarity: 0.102M 0.114M (55.0mL) (0.102M) (35.0mL)(0.114M) = 3.99 x 10' moles moles: = 5.61x10'moles -

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