A A A B В В Concentration of sugar Concentration of sugar А 36% В 15% Concentration of sugar A 21% В 60% Solution is A 44% В 21% Solution is Solution is A A A B B Concentration of sugar Concentration of sugar Concentration of sugar A 58% В 25% Solution is А 30% в 30% Solution is A 0% В 35 Solution is A A A B В B Concentration of sugar Concentration of sugar Α 10% В 40% A 8% В 50% Concentration of sugar A 15% В 45% Solution is Solution is Solution is
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In each problem below draw an arrow showing which way water will move/flow.
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- 5 please provide complete solution and explanationTable 2. Volume of BSA, protein content, and absorbance readings of reference solutions Solution Volume of BSA standard solution (μL) Protein content(μg/mL) Absorbance value At 595 nm 1 0 0 0 2 10 1 0.022 3 30 3 0.065 4 50 5 0.106 5 70 7 0.178 6 100 10 0.299 7 120 12 0.380 Make a graph by plotting the absorbance values versus the BSA protein content (in μg) for theseven reference solutions. When constructing the graph, be…4. Attheendoftheprocedureforthisexperiment,arecrystallizationisdoneina mixed solvent system. Which solvents are used? In which solvent is caffeine LESS SOLUBLE? Briefly explain the significance (i.e. why it is done) of adding one of the two solvents, “to turn the solution faintly cloudy,” during the recrystallization
- Calculate protein concentration in unknown samples 1, 2, 3: Absorbance of Unknown 1 = 0.541 Absorbance of Unknown 2 = 0.85 Absorbance of Unknown 3 = 1.02 Standard Curve: Y = 0.0073xHi! can you show the solution through a punnet square?0% 25% 50% 75% 100% Depth of H2O2 Solution (d) 2.1 cm 2.1 cm 2.1 cm 2.1 cm 2.1 cm Trial 1 Time 180 sec 84.61 sec 43.52 sec 36.90sec 25.90 sec Trial 2 Time 180 sec 92.25 sec 38.16 sec 34.36 sec 23.57sec Trial 3 Time 32.53 sec 18.82 sec Average Time (t) 180 sec 88.43 sec 40.84 Sec 34.5 sec 22.76 sec Rate of the Reaction(R = d/t) 0.012 cm/sec 0.02 cm/sec 0.051 cm/sec 0.061 cm/sec 0.0923cm/sec graph rate of reaction on the y-axis and percent concentration of enzyme on the x-axis. If the points are linear, draw a “best-fit” straight line through or near all of the data points. Based on the information in the data table and your graph, explain the relationship between percent concentration of catalase and rate of reaction.
- Prepare the following solutions1. 250.0 mL 0.0100 M working EDTA solution from 0.1000 M EDTA 2. 50.0 mL 0.0050 M working standard Ca2+ solution from 0.0500 M Ca2+3. 25.0 mL 4.0 M MnSO4 from MnSO4·2H2O crystalsSample Relative Concentration of Tea Extracts % Inhibition Green Tea ( 0.25 mg ) 0.25 0.974 Green Tea ( 0.5 mg ) 0.5 0.967 Green Tea ( 0.75 mg ) 0.75 0.965 Green Tea ( 1.5 mg ) 1.5 0.959 Back tea ( 0.25 mg ) 0.25 0.858 Black tea ( 0.5 mg ) 0.5 0.976 Back tea ( 0.75 mg ) 0.75 0.982 Black tea ( 1.5 mg ) 1.5 0.969 plot the graphShow the calculations required to make up 250mlof a stock solution of this chemical that will then be at the working concentration when 1 volume of this solution is added to 10 volumes of cell culture medium.
- witj the following imformation create figures and explain the resultsA 2.5mg/ml solution of ampicillin is available for use, what volume would youadd to 200ml of LB medium to obtain a final concentration of 50µg/ml ofampicillin?Time point (min) Absorbance of culture at 660nm Approximate cell concentration Approximate # cells in 1mL extract 0 0.298 1.49 x 108 cells/mL 1.49 x 108 cells 10 0.316 1.58 x 108 cells/mL 1.58 x 108 cells 20 0.374 1.87 x 108 cells/mL 1.87 x 108 cells 30 0.429 2.145 x 108 cells/mL 2.145 x 108 cells 40 0.512 2.56 x 108 cells/mL 2.56 x 108 cells 50 0.544 2.72 x 108 cells/mL 2.72 x 108 cells 60 0.607 3.035 x 108 cells/mL 3.035 x 108 cells a. Using these data, prepare a growth curve of this strain ofEscherichia coli (E. coli).b. Estimate the doubling time for this strain of E. Coli. Clearly showhow you estimated this value from the empirical data presented.