a) Are the body mass leanness and heat-loss ratecorrelated? Explain your reasoning.   b) Calculate the standard error of the correlation coefficient; what does this value represent?Using the standard error how do you report (write) your results in a scientific paper?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 70E
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a) Are the body mass leanness and heat-loss ratecorrelated? Explain your reasoning.

 

b) Calculate the standard error of the correlation coefficient; what does this value represent?Using the standard error how do you report (write) your results in a scientific paper? 

3. To investigate whether subcutaneous fat provides insulation in humans, Sloan and Leatinge (1973) measured the
rate of heat loss by boys swimming for up to 40 minutes in water at 20.3 °C and expending energy at about 4.8
kcal/min. Heat loss was measured by the change in body temperature, recorded using a thermometer under the tongue,
divided by time spent swimming, in minutes. The authors measured an index of body "leanness" on 12 boys as the
reciprocal of the skin-fold thickness adjusted for total skin surface area (in meters squared) and body mass (in kg).
X =3.96667
Y = 0.04833
E (X, -X) = 41.14667
E(Y, -Y)' =0.01696
E (X, -X)(Y, – Y)=0.78053
Transcribed Image Text:3. To investigate whether subcutaneous fat provides insulation in humans, Sloan and Leatinge (1973) measured the rate of heat loss by boys swimming for up to 40 minutes in water at 20.3 °C and expending energy at about 4.8 kcal/min. Heat loss was measured by the change in body temperature, recorded using a thermometer under the tongue, divided by time spent swimming, in minutes. The authors measured an index of body "leanness" on 12 boys as the reciprocal of the skin-fold thickness adjusted for total skin surface area (in meters squared) and body mass (in kg). X =3.96667 Y = 0.04833 E (X, -X) = 41.14667 E(Y, -Y)' =0.01696 E (X, -X)(Y, – Y)=0.78053
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