A bacterial suspension with a population of 6.3 x 107cells/mL was diluted as follows: 4 mL was removed and added to 16 mL of diluent. This was again diluted 1 in 300. Determine the concentration of cells after EACH dilution. Concentration after the 1st dilution = 6.3 x 107 cells/mL x 1/5 = 12.6 x 106 cells/mL Concentration after the 2nd dilution = 12.6 x 106 cells/mL x 1/300 = 42000 cells/mL
A bacterial suspension with a population of 6.3 x 107cells/mL was diluted as follows: 4 mL was removed and added to 16 mL of diluent. This was again diluted 1 in 300. Determine the concentration of cells after EACH dilution. Concentration after the 1st dilution = 6.3 x 107 cells/mL x 1/5 = 12.6 x 106 cells/mL Concentration after the 2nd dilution = 12.6 x 106 cells/mL x 1/300 = 42000 cells/mL
Chapter10: Reconstitution Of Powdered Drugs
Section: Chapter Questions
Problem 8.1P
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A bacterial suspension with a population of 6.3 x 107cells/mL was diluted as follows:
4 mL was removed and added to 16 mL of diluent. This was again diluted 1 in 300.
Determine the concentration of cells after EACH dilution.
Concentration after the 1st dilution = 6.3 x 107 cells/mL x 1/5 = 12.6 x 106 cells/mL
Concentration after the 2nd dilution = 12.6 x 106 cells/mL x 1/300 = 42000 cells/mL
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