(a) Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 7.00 x 105 kg hangs motionless on it. (Enter a number.) 6.86 (b) Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure. 5.0° Ta T₁ W 1 -5.0° The strand sags at an angle of 13.0° below the horizontal. (Enter a number.) 1.5250 N Compare this with the tension in the vertical strand (find their ratio). (Enter a number.) (tension in horizontal strand)/(tension in vertical strand) = 2.223

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter4: Newton's Laws Of Motion
Section4.6: Applications Of Newton's Laws
Problem 4.9QQ: For the woman being pulled forward on the toboggan in Figure 4.33, is the magnitude of the normal...
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(a) Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 7.00 x 105 kg hangs motionless on it. (Enter a number.)
6.86
N
(b) Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure.
5.0⁰
x
TR
T₁
TR
5.0°
Ⓡ
The strand sags at an angle of 13.0° below the horizontal. (Enter a number.)
1.5250
N
Compare this with the tension in the vertical strand (find their ratio). (Enter a number.)
(tension in horizontal strand)/(tension in vertical strand) = 2.223
Transcribed Image Text:(a) Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 7.00 x 105 kg hangs motionless on it. (Enter a number.) 6.86 N (b) Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure. 5.0⁰ x TR T₁ TR 5.0° Ⓡ The strand sags at an angle of 13.0° below the horizontal. (Enter a number.) 1.5250 N Compare this with the tension in the vertical strand (find their ratio). (Enter a number.) (tension in horizontal strand)/(tension in vertical strand) = 2.223
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