A chemist is studying the following equilibirum, which has the given equilibrium constant at a certain temperature: N2(g) + 2H,O(g)=2 NO(g) + 2H2(8) = 4. x 10 He fills a reaction vessel at this temperature with 10. atm of nitrogen gas and 28. atm of water vapor. Use this data to answer the questions in the table below. Can you predict the equilibrium pressure of H2, using only the tools O yes available to you within ALEKS? O no If you said yes, then enter the equilibrium pressure of H, at right. I atm Round your answer to 1 significant digit.

World of Chemistry, 3rd edition
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Chapter17: Equilibrium
Section: Chapter Questions
Problem 39A
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A chemist is studying the following equilibirum, which has the given equilibrium constant at a certain temperature:
N2(g) + 2 H,0(g)= 2 NO(g) + 2 H2(g)
K = 4. x 10-9
He fills a reaction vessel at this temperature with 10. atm of nitrogen gas and 28. atm of water vapor. Use this data to answer the questions in the table below.
yes
Can you predict the equilibrium pressure of H,, using only the tools
available to you within ALEKS?
O no
If you said yes, then enter the equilibrium pressure of H, at right.
Round your answer to 1 significant digit.
I atm
Transcribed Image Text:A chemist is studying the following equilibirum, which has the given equilibrium constant at a certain temperature: N2(g) + 2 H,0(g)= 2 NO(g) + 2 H2(g) K = 4. x 10-9 He fills a reaction vessel at this temperature with 10. atm of nitrogen gas and 28. atm of water vapor. Use this data to answer the questions in the table below. yes Can you predict the equilibrium pressure of H,, using only the tools available to you within ALEKS? O no If you said yes, then enter the equilibrium pressure of H, at right. Round your answer to 1 significant digit. I atm
Expert Solution
Step 1

Given:

pressure of N2 gas = 10.0 atm

pressure of water vapor = 28.0 atm

 

Step 2

Balanced chemical equation is given by,

N2(g)+2H2O(g)2NO(g)+2H2(g)                    Kp=4.0×10-9

Step 3

ICE table is given by,

  N2 H2O NO H2
Initial (atm) 10.0 28.0 0.0 0.0
Change (atm) -x -2x +2x +2x
Equilibrium (atm) 10.0 - x 28.0 - x 2x 2x
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