A chemist titrates 190.0 mL of a 0.1045 M aniline (C,H,NH,) solution with 0.5131 M HBr solution at 25 °C. Calculate the pH at equivalence. The p K, of aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added.

Chemistry: Principles and Reactions
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Chapter14: Equilibria In Acid-base Solutions
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Problem 74QAP: Fifty cm3 of 1.000 M nitrous acid is titrated with 0.850 M NaOH. What is the pH of the solution (a)...
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Calculating the pH at equivalence of a titration
A chemist titrates 190.0 mL of a 0.1045M aniline (C,H,NH,) solution with 0.5131 M HBr solution at 25 °C. Calculate the pH at equivalence. The p K, of
aniline is 4.87.
Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added.
pH = 0
Transcribed Image Text:A chemist titrates 190.0 mL of a 0.1045M aniline (C,H,NH,) solution with 0.5131 M HBr solution at 25 °C. Calculate the pH at equivalence. The p K, of aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = 0
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