A chunk of Zn was breaks down on 200 mL of 0.750 mol/Liter Hydrochloric acid. After that rx, 100 mL of solution is diluted to 400 ml and titrated with 15 ml of 0.250 mol/Liter solution of Sodium Hydroxide until the endpoint. Find the: The exact number of moles of hydrochloric acid in the 200 mL solution Exact number of moles of excess hydrochloric acid which reacted with sodium hydroxide in the 100 mL sampl3 Number of moles of excess hydrochloric acid in the 200 mL solution (first solution)
A chunk of Zn was breaks down on 200 mL of 0.750 mol/Liter Hydrochloric acid. After that rx, 100 mL of solution is diluted to 400 ml and titrated with 15 ml of 0.250 mol/Liter solution of Sodium Hydroxide until the endpoint. Find the: The exact number of moles of hydrochloric acid in the 200 mL solution Exact number of moles of excess hydrochloric acid which reacted with sodium hydroxide in the 100 mL sampl3 Number of moles of excess hydrochloric acid in the 200 mL solution (first solution)
Chemical Principles in the Laboratory
11th Edition
ISBN:9781305264434
Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Chapter24: The Standardization Of A Basic Solution And The Determination Of The Molar Mass Of An Acid
Section: Chapter Questions
Problem 3ASA: A 0.3012g sample of an unknown monoprotic acid requires 24.13mL of 0.0944MNaOH for neutralization to...
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A chunk of Zn was breaks down on 200 mL of 0.750 mol/Liter Hydrochloric acid. After that rx, 100 mL of solution is diluted to 400 ml and titrated with 15 ml of 0.250 mol/Liter solution of Sodium Hydroxide until the endpoint.
Find the:
- The exact number of moles of hydrochloric acid in the 200 mL solution
- Exact number of moles of excess hydrochloric acid which reacted with sodium hydroxide in the 100 mL sampl3
- Number of moles of excess hydrochloric acid in the 200 mL solution (first solution)
- Number of moles of Zn which reacted with hydrochloric acid
- Mass of the chunk of Zn which was dissolved
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