A coffee owner wanted to determine how much caffeine was in each cup of coffee being served. A caffeine content analysis was performed on eight different 100.0 g samples of coffee, and the data is shown in the table below. For reference, each 100.0 g of coffee served should have 40 mg of caffeine present.
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- In a study conducted to examine the quality of fish after 7 days in ice storage, ten raw fish of the same kind and approximately the same size were caught and prepared for ice storage. The fish were placed in ice storage at different times after being caught. A measure of fish quality was given to each fish after 7 days in ice storage. The sample data are shown below, where "Time" is the number of hours after being caught that the fish was placed in ice storage and "Fish Quality" is the measure given to each fish after 7 days in ice storage (higher numbers mean better quality). Which variable would be considered the response variable? Fish Time: 0 0 2 3 5 6 7 9 11 12 Fish Quality 8.5 8.4 8.0 8.1 7.8 7.6 7.3 7.0 6.8 6.7 Choose the correct answer below. A.Fish Quality B.Time C.Neither variable could be considered a response variable.A paper gave information on sodium content for various types of foods. Twenty-six tomato catsups were analyzed. Data consistent with summary quantities given in the paper are shown in the table. Sodium content (mg/kg) 12,178 10,426 10,912 9,116 13,226 11,663 11,781 10,680 8,457 10,788 12,605 10,591 11,040 10,815 12,962 11,644 10,047 10,468 10,108 12,353 11,738 11,092 11,673 8,758 11,145 11,495 Calculate the values of the quartiles and the interquartile range. 1st quartile 3rd quartileinterquartile rangeA paper gave information on sodium content for various types of foods. Twenty-six tomato catsups were analyzed. Data consistent with summary quantities given in the paper are shown in the table. Sodium content (mg/kg) 12,178 10,426 10,912 9,116 13,226 11,663 11,781 10,680 8,457 10,788 12,605 10,591 11,040 10,815 12,962 11,644 10,047 10,498 10,108 12,353 11,758 11,092 11,673 8,758 11,145 11,495 Calculate the values of the quartiles and the interquartile range. 1st quartile 3rd quartileinter quartile range
- The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who were vegans and another sample of such women who were omnivores. Diet Sample Size Sample Mean Sample SD Vegan 86 5.30 1.02 Omnivore 93 5.75 1.20 Calculate a 99% CI for the difference between population mean total cholesterol level for vegans and population mean total cholesterol level for omnivores. (Use ?Vegan − ?Omnivore. Round your answers to three decimal places.) , (mmol/l) Interpret the interval. We are 99% confident that the true average cholesterol level for vegans is greater than that of omnivores by an amount within the confidence interval.We are 99% confident that the true average cholesterol level for vegans is less than that of omnivores by an amount within the confidence interval. We are 99% confident that the true average cholesterol level for vegans is greater than that of omnivores by an amount outside…Periodically, the county Water Department tests the drinking water of homeowners for contminants such as lead and copper. The lead and copper levels in water specimens collected in 1998 for a sample of 10 residents of a subdevelopement of the county are shown below. lead (?μg/L) copper (mg/L) 3.33.3 0.6280.628 3.33.3 0.2930.293 0.30.3 0.7830.783 4.74.7 0.1950.195 55 0.3780.378 1.41.4 0.2330.233 0.90.9 0.1010.101 0.90.9 0.6980.698 3.63.6 0.80.8 1.21.2 0.7610.761 (a) Construct a 99% confidence interval for the mean lead level in water specimans of the subdevelopment. _____≤μ≤_____ (b) Construct a 99% confidence interval for the mean copper level in water specimans of the subdevelopment. ______≤μ≤______Fifteen adult males between the ages of 35 and 50 participated in a study to evaluate the effect of diet and exercise on blood cholesterol levels. The total cholesterol was measured in each subject initially and then three months after participating in an aerobic exercise program and switching to a low-fat diet. The data are shown in the following table.
- A researcher reports an F-ratio with dfbetween = 2 and dfwithin = 30 for an independent-measures ANOVA. a. How many treatment conditions were compared in the experiment? b. How many subjects participated ion the experiment?A paper gave summary quantities for blood lead level (in micrograms per deciliter) for a sample of whites and a sample of African Americans. Data consistent with the given summary quantities is given below. Whites (W) 8.3 0.9 2.9 5.6 5.8 5.4 1.2 1.0 1.4 2.1 1.3 5.3 8.4 6.6 5.2 3.4 2.9 2.7 6.7 3.6 African Americans (AA) 4.8 1.4 0.9 10.8 2.4 0.6 5.0 5.4 6.1 2.9 5.0 2.1 7.5 3.4 13.6 1.4 3.7 3.3 14.8 3.9 (a) Calculate the values of the mean and the median for blood lead level for the sample of African Americans. mean median (b) Which of the mean or the median is larger? What characteristic of the data set explains the relative values of the mean and the median? The median is greater than the mean. This is explained by the fact that the distribution is positively skewed. The mean is greater than the median. This is explained by the fact that the distribution is positively skewed. The median is greater than the mean. This is explained by the fact that the…A regional survey wass carried out to gauge public opin ion on the contro versial Arizona Immigration Law. Based on the results displayed in the table below, what percent of respondentsis independent? Response Democrat Republican Independent Favor 50 93 35 Oppose 85 45 60 Dont't know 5 7 20
- A paper gave summary quantities for blood lead level (in micrograms per deciliter) for a sample of whites and a sample of African Americans. Data consistent with the given summary quantities is given below. Whites (W) 8.3 0.9 2.9 5.6 5.8 5.4 1.2 1.0 1.4 2.1 1.3 5.3 8.4 6.6 5.2 3.6 2.9 2.7 6.7 3.8 African Americans (AA) 4.8 1.4 0.9 10.8 2.4 0.6 5.0 5.4 6.1 2.9 5.0 2.1 7.5 3.4 13.4 1.4 3.9 3.3 14.8 4.1 (a) Calculate the values of the mean and the median for blood lead level for the sample of African Americans. meanmedian (b) Which of the mean or the median is larger? What characteristic of the data set explains the relative values of the mean and the median? The mean is greater than the median. This is explained by the fact that the distribution is positively skewed.The median is greater than the mean. This is explained by the fact that the distribution is positively skewed. The median is greater than the mean. This is explained by the fact that the…The department of zoology at the Virginia Polytechnic Institute and State University carried out a study to determine if there is a significant difference in the density of organisms in two different stations located in Cedar Run, a secondary river that is located in the river basin. Roanoke. Drainage from a sewage treatment plant and overflow from the Federal Mogul Corporation sedimentation pond enter the flow near the source of the river. The following data give the density measurements, in numbers of organisms per square meter, at the two different collecting stations. Number of organisms per square meter Station 1 Station 2 5030 2800 13700 4670 10730 6890 11400 7720 860 7030 2200 7330 4250 2810 15040 1330 4980 3320 11910 1230 8130 2130 26850 2190 17660 22800 1130 1690 With a significance level of 0.05, can we conclude that the densities are the same in the two…Two quality control technicians measured the surface finish of a metal part, obtaining the data in the table below. Assume that the measurements are normally distributed.